如何在Sql中将行转换为列

我有一个表

列

以及第二个表

Response

，其中保存了所有数据

现在我想创建一个SQL视图，其中的结果应该如下

;with cte as 
(
    select r.*, 
    c.name 
    from Response r 
        inner join Columns c
            on r.columnid = c.id
) 
select 
    Userid, 
    max([FromDate]) as [FromDate],
    max([ToDate]) as [ToDate],
    max([Project]) as [Project],
    max([Comment]) as [Comment] 
from cte
pivot
(
    max(Text) for name in ([FromDate], [ToDate], [Project], [Comment])
) p
group by userid

我试着用pivot

select UserId ,FromDate, ToDate, Project, Comment
from
(
  select R.UserId ,R.Text , C.ColumnName
  from [Columns] C
  INNER JOIN Response R ON C.Id=R.ColumnId
) d
pivot
(
  max(Text)
  for ColumnName in (FromDate, ToDate, Project, Comment)
) piv;

但这对我不起作用，我也提到了这一点，但无法实施。如何在SQL视图中实现同样的功能

表的脚本：

CREATE TABLE [dbo].[Columns](
    [Id] [bigint] IDENTITY(1,1) NOT NULL,
    [Name] [nvarchar](1000) NULL,
    [IsActive] [bit] NULL,
 CONSTRAINT [PK_Columns] PRIMARY KEY CLUSTERED 
(
    [Id] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO

insert into [Columns] values('FromDate',1)
insert into [Columns] values('ToDate',1)
insert into [Columns] values('Project',1)
insert into [Columns] values('Comment',1)

CREATE TABLE [dbo].[Response](
    [Id] [bigint] IDENTITY(1,1) NOT NULL,
    [UserId] [bigint]  NOT NULL,
    [ColumnId] [bigint]  NOT NULL,
    [Text] [nvarchar](max) NULL,
    [IsActive] [bit] NULL,
    CONSTRAINT [PK_Response] PRIMARY KEY CLUSTERED 
(
    [Id] ASC
)WITH (PAD_INDEX  = OFF, STATISTICS_NORECOMPUTE  = OFF, IGNORE_DUP_KEY = OFF, ALLOW_ROW_LOCKS  = ON, ALLOW_PAGE_LOCKS  = ON) ON [PRIMARY]
) ON [PRIMARY]

GO
insert into [Response] values(1,1,'1/1/2012',1)
insert into [Response] values(1,2,'1/2/2012',1)
insert into [Response] values(1,3,'p1',1)
insert into [Response] values(1,4,'c1',1)
insert into [Response] values(2,1,'1/1/2013',1)
insert into [Response] values(2,2,'1/2/2013',1)
insert into [Response] values(2,3,'p2',1)
insert into [Response] values(2,4,'c2',1)
insert into [Response] values(2,1,'1/1/2014',1)
insert into [Response] values(2,2,'1/2/2014',1)
insert into [Response] values(2,3,'p3',1)
insert into [Response] values(2,4,'c3',1)
insert into [Response] values(3,1,'1/1/2015',1)
insert into [Response] values(3,2,'1/2/2015',1)
insert into [Response] values(3,3,'p4',1)
insert into [Response] values(3,4,'c4',1)

---

您可以这样查询

;with cte as 
(
    select r.*, 
    c.name 
    from Response r 
        inner join Columns c
            on r.columnid = c.id
) 
select 
    Userid, 
    max([FromDate]) as [FromDate],
    max([ToDate]) as [ToDate],
    max([Project]) as [Project],
    max([Comment]) as [Comment] 
from cte
pivot
(
    max(Text) for name in ([FromDate], [ToDate], [Project], [Comment])
) p
group by userid

---

试试这个。我已经准备好了你的答案

select UserId ,FromDate, ToDate, Project, Comment
from
(
  select R.UserId ,R.RText , C.ColumnName
  from [Columns] C
  INNER JOIN Response R ON C.Id=R.ColumnId
) d
pivot
(
  Min(Rtext)
  for ColumnName in (FromDate, ToDate, Project, Comment)
) piv

UNION
select UserId ,FromDate, ToDate, Project, Comment
from
(
  select R.UserId ,R.RText , C.ColumnName
  from [Columns] C
  INNER JOIN Response R ON C.Id=R.ColumnId
) d
pivot
(
  Max(Rtext)
  for ColumnName in (FromDate, ToDate, Project, Comment)
) piv;

---

老实说，如果列类型不会改变，或者您只需要它们的一个子集，您可以将它们过滤掉，然后加入它们，而不是编写一个透视。我使用cte编写了它，但它们也很容易成为子查询：

;with fd as
(
    select
        UserID,
        [Text] as FromDate,
        row_number() over (partition by userID order by ID) as DEDUP
    from response
    where ColumnID = 1
),
td as
(
    select
        UserID,
        [Text] as ToDate,
        row_number() over (partition by userID order by ID) as DEDUP
    from response
    where ColumnID = 2
),
p as
(
    select
        UserID,
        [Text] as Project,
        row_number() over (partition by userID order by ID) as DEDUP
    from response
    where ColumnID = 3
),
c as
(
    select
        UserID,
        [Text] as Comment,
        row_number() over (partition by userID order by ID) as DEDUP
    from response
    where ColumnID = 4
)
select
    fd.*,
    td.ToDate,
    p.Project,
    c.Comment
from fd
    inner join td
        on fd.UserId = td.UserId
            and fd.DEDUP = td.DEDUP
    inner join p
        on fd.UserId = p.UserId
            and fd.DEDUP = p.DEDUP
    inner join c
        on fd.UserId = c.UserId
            and fd.DEDUP = c.DEDUP

---

---

显示对您不起作用的内容。您可以显示您尝试使用的pivot查询吗？@WEI_DBA:shared当一个用户ID在多个项目上时会发生什么情况？@DForck42：正如我在问题中提到的所需输出，对应的

用户ID

的每条记录都应该没有重复记录。答案中有两个问题，

1

：

max

函数为

date

类型值返回null，此处为

FromDate

和

Todate

列<代码>2：对于

UserId=2

只返回1行作为脚本提供输入示例数据共享基于输入脚本的脚本支持的答案。这对我来说很好。我没有得到project

p2

的结果，你是真的运行了你在回答中提到的查询，还是只是编辑并发布在这里。另外，我没有否决你的答案。

max

和

min

函数为日期类型值返回null，这里为

FromDate

和

Todate

列返回null。另外，对于UserId=2，您只考虑两行，对于任何UserIdTrue，可以有更多行。我是根据您的数据进行查询的。您的查询返回重复的记录，是否有任何方法可以获得唯一的记录。@SidM我纠正了我的输入错误。让我知道这是否正确现在不，它仍然提供副本results@SidM好的，我想我已经修好了谢谢你的回答：）