如何在TSQL中拆分数据
需要一些关于如何分割数据的帮助吗 当前的数据如下所示如何在TSQL中拆分数据,sql,sql-server,tsql,unpivot,Sql,Sql Server,Tsql,Unpivot,需要一些关于如何分割数据的帮助吗 当前的数据如下所示 ╔═════════════════════════════════════════════╗ ║ Name Data1 Data2 Data3 Field1 field2 Field3 ║ ╠═════════════════════════════════════════════╣ ║ a 1 2 3 x y z ║ ╚══════════════════════════════
╔═════════════════════════════════════════════╗
║ Name Data1 Data2 Data3 Field1 field2 Field3 ║
╠═════════════════════════════════════════════╣
║ a 1 2 3 x y z ║
╚═════════════════════════════════════════════╝
+-----------------+
| name data field |
+-----------------+
| a 1 x |
| a 2 y |
| a 3 z |
+-----------------+
我需要分割数据,使其看起来像这样
╔═════════════════════════════════════════════╗
║ Name Data1 Data2 Data3 Field1 field2 Field3 ║
╠═════════════════════════════════════════════╣
║ a 1 2 3 x y z ║
╚═════════════════════════════════════════════╝
+-----------------+
| name data field |
+-----------------+
| a 1 x |
| a 2 y |
| a 3 z |
+-----------------+
有人能帮我做这件事吗?有很多方法可以做到这一点(只需看看蓝脚的答案),但一个简单的方法是使用
UNION ALL
:
SELECT [Name], Data1 AS Data, Field1 AS Field
FROM YourTable
UNION ALL
SELECT [Name], Data2 AS Data, Field2 AS Field
FROM YourTable
UNION ALL
SELECT [Name], Data3 AS Data, Field3 AS Field
FROM YourTable
还有一个演示(由蓝脚提供)。取决于您的SQL Server版本。从SQL Server 2008开始,您可以使用
交叉应用
:
SELECT t.name,
x.Data,
x.Field
FROM YourTable t
CROSS APPLY
(
VALUES
(t.Data1, t.Field1),
(t.Data2, t.Field2),
(t.Data3, t.Field3)
) x (Data, Field);
看
这也可以使用SQL Server 2005+中的UNPIVOT
和PIVOT
函数来完成:
select name, data, field
from
(
select name, left(col, len(col) -1) col, value,
row_number() over(partition by left(col, len(col) -1) order by col) rn
from
(
select name,
cast([Data1] as varchar(10)) Data1,
cast([Data2] as varchar(10)) Data2,
cast([Data3] as varchar(10)) Data3,
[Field1], [field2], [Field3]
from yourtable
) src
unpivot
(
value
for col in ([Data1], [Data2], [Data3],
[Field1], [field2], [Field3])
) unpiv
) u
pivot
(
max(value)
for col in (data,field)
) piv
看
两者都给出了结果:
| NAME | DATA | FIELD |
-----------------------
| a | 1 | x |
| a | 2 | y |
| a | 3 | z |
此查询还将水平表转换为垂直表。如果你想让它保持并查询它,就把它变成一个视图。在2005年,使用
UNION ALL
可以实现同样的效果。我如何将交叉应用的结果转储到一个表中?@Greg你可以使用SELECT-into-newtable
-看到这个演示--@ethrbunny在两个答案后问这个问题?