Sql 在BigQuery中按2列进行分区

假设我想对每个公寓的前3个月收入和收入金额进行排名，我可以执行以下操作，没有问题：

Select * FROM (SELECT Flat,
EXTRACT(YEAR FROM pay_day) AS Year,
EXTRACT(MONTH FROM pay_day) AS Month,
RANK() OVER(PARTITION BY Flat ORDER BY SUM(USD_amt) DESC) AS rank, 
SUM(USD_amt) AS Revenue
FROM `finances.reservations` AS f
GROUP BY Flat, Year, Month)
WHERE rank<=3 AND Flat IS NOT NULL
ORDER BY Flat, Year, Rank, Month 
ASC

但现在，如果说我想要每个单位每年的前3个月，我想我只需要按年份修改分区如下：

RANK() OVER(PARTITION BY Flat, EXTRACT(YEAR FROM pay_day) ORDER BY SUM(USD_amt) DESC) AS rank

Field name            | Type    | Mode
----------------------+---------+------------
Flat                  | STRING  | NULLABLE
pay_day               | DATE    | NULLABLE
nights                | INTEGER | NULLABLE
check_in              | DATE    | NULLABLE
check_out             | DATE    | NULLABLE
nights__in_month_     | STRING  | NULLABLE
nights_outside_month_ | STRING  | NULLABLE
cleaning              | INTEGER | NULLABLE
currency              | STRING  | NULLABLE
USD_amt               | INTEGER | NULLABLE
EANR                  | STRING  | NULLABLE
name                  | STRING  | NULLABLE
people                | INTEGER | NULLABLE
country               | STRING  | NULLABLE
reservation_no_       | STRING  | NULLABLE
payment_processor     | STRING  | NULLABLE
Check_in_day          | STRING  | NULLABLE
Cleaner               | STRING  | NULLABLE
Review                | STRING  | NULLABLE

我希望结果是这样的：

   Flat Year Month Rank Revenue
    1   2019    12  1   3281
    1   2019    4   2   3031
    1   2019    1   3   2031
    1   2020    4   1   3031
    1   2020    9   2   3001
    1   2020    7   3   2919

但这会导致一个错误“按表达式划分引用pay_day列，该列在[4:50]时既没有分组也没有聚合”，我想知道我做错了什么

表架构如下所示：

RANK() OVER(PARTITION BY Flat, EXTRACT(YEAR FROM pay_day) ORDER BY SUM(USD_amt) DESC) AS rank

Field name            | Type    | Mode
----------------------+---------+------------
Flat                  | STRING  | NULLABLE
pay_day               | DATE    | NULLABLE
nights                | INTEGER | NULLABLE
check_in              | DATE    | NULLABLE
check_out             | DATE    | NULLABLE
nights__in_month_     | STRING  | NULLABLE
nights_outside_month_ | STRING  | NULLABLE
cleaning              | INTEGER | NULLABLE
currency              | STRING  | NULLABLE
USD_amt               | INTEGER | NULLABLE
EANR                  | STRING  | NULLABLE
name                  | STRING  | NULLABLE
people                | INTEGER | NULLABLE
country               | STRING  | NULLABLE
reservation_no_       | STRING  | NULLABLE
payment_processor     | STRING  | NULLABLE
Check_in_day          | STRING  | NULLABLE
Cleaner               | STRING  | NULLABLE
Review                | STRING  | NULLABLE

---

我想您可以在BigQuery中引用列别名：

SELECT *
FROM (SELECT Flat, EXTRACT(YEAR FROM pay_day) AS Year,
             EXTRACT(MONTH FROM pay_day) AS Month,
             RANK() OVER (PARTITION BY Flat, Year ORDER BY SUM(USD_amt) DESC) AS rank, 
             SUM(USD_amt) AS Revenue
      FROM `finances.reservations` AS f
      GROUP BY Flat, Year, Month
     ) ym
WHERE rank <= 3 AND Flat IS NOT NULL
ORDER BY Flat, Year, Rank, Month ASC

GROUP BY

范围内的最小日期具有相同的年份，因此实际上是相同的。我意识到这就是我通常处理这个问题的方式