Sql 多个表的“按日期分组”
(我正在使用postgres) 我有两个来自不同表的查询。每个都按日期分组。 将它们联接到一个查询(联合或联接)的最佳方式是什么? 提前谢谢 质疑№1:Sql 多个表的“按日期分组”,sql,postgresql,join,group-by,union,Sql,Postgresql,Join,Group By,Union,(我正在使用postgres) 我有两个来自不同表的查询。每个都按日期分组。 将它们联接到一个查询(联合或联接)的最佳方式是什么? 提前谢谢 质疑№1: SELECT to_char(date,'MM') as mon, extract(year from date) as yyyy, SUM("table_1"."user_money") AS user_sum, SUM("table_1"."system_money") AS system_sum
SELECT to_char(date,'MM') as mon,
extract(year from date) as yyyy,
SUM("table_1"."user_money") AS user_sum,
SUM("table_1"."system_money") AS system_sum
FROM "table_1"
GROUP BY 1,2
ORDER BY 2,1;
mon | yyyy | user_sum | system_sum
-----+------+------------------+-----------------
11 | 2015 | 10 | 50
12 | 2015 | 20 | 60
(2 rows)
查询结果№1:
SELECT to_char(date,'MM') as mon,
extract(year from date) as yyyy,
SUM("table_1"."user_money") AS user_sum,
SUM("table_1"."system_money") AS system_sum
FROM "table_1"
GROUP BY 1,2
ORDER BY 2,1;
mon | yyyy | user_sum | system_sum
-----+------+------------------+-----------------
11 | 2015 | 10 | 50
12 | 2015 | 20 | 60
(2 rows)
质疑№2:
SELECT to_char(created_at,'MM') as mon,
extract(year from created_at) as yyyy,
SUM("table_2"."amount") AS payments_sum
FROM "table_2"
GROUP BY 1,2
ORDER BY 2,1;
mon | yyyy | payments_sum
-----+------+--------------
10 | 2015 | 500
11 | 2015 | 600
12 | 2015 | 700
01 | 2016 | 800
(4 rows)
查询结果№2:
SELECT to_char(created_at,'MM') as mon,
extract(year from created_at) as yyyy,
SUM("table_2"."amount") AS payments_sum
FROM "table_2"
GROUP BY 1,2
ORDER BY 2,1;
mon | yyyy | payments_sum
-----+------+--------------
10 | 2015 | 500
11 | 2015 | 600
12 | 2015 | 700
01 | 2016 | 800
(4 rows)
所需结果:
mon | yyyy | payments_sum | user_sum | system_sum
-----+------+--------------+------------------+----------------
10 | 2015 | 500 | |
11 | 2015 | 600 | 10 | 50
12 | 2015 | 700 | 20 | 60
01 | 2016 | 800 | |
(4 rows)
试试这个
SELECT
to_char(date,'MM') as mon,
extract(year from date) as yyyy,
SUM("table_2"."amount") AS payments_sum,
SUM("table_1"."user_money") AS user_sum,
SUM("table_1"."system_money") AS system_sum
FROM
"table_1"
LEFT JOIN
"table_2" ON (to_char("table_1"."date", 'MM') = to_char("table_2"."date", 'MM') AND extract(year from "table_1"."date") = extract(year from "table_2"."date"))
GROUP BY 1,2
ORDER BY 2,1;
我认为您可以将每个查询视为子查询,然后与完整的外部联接相结合。联盟可能不是你想要的 大概是这样的:
SELECT * FROM
(SELECT to_char(date,'MM') as mon,
extract(year from date) as yyyy,
SUM("table_1"."user_money") AS user_sum,
SUM("table_1"."system_money") AS system_sum
FROM "table_1"
GROUP BY 1,2) AS q1
FULL OUTER JOIN
(SELECT to_char(created_at,'MM') as mon,
extract(year from created_at) as yyyy,
SUM("table_2"."amount") AS payments_sum
FROM "table_2"
GROUP BY 1,2) AS q2
ON q1.mon = q2.mon AND q1.yyyy = q2.yyyy
ORDER BY 2,1
在mon和yyyy值匹配的位置进行连接。这里是另一个更符合PostgreSQL特定语法的连接:
WITH query_one AS (
SELECT
to_char(date,'MM') as mon,
extract(year from date) as yyyy,
SUM("table_1"."user_money") AS user_sum,
SUM("table_1"."system_money") AS system_sum
FROM
"table_1"
GROUP BY
1,2
), query_two AS (
SELECT
to_char(created_at,'MM') as mon,
extract(year from created_at) as yyyy,
SUM("table_2"."amount") AS payments_sum
FROM
"table_2"
GROUP BY
1,2
)
SELECT
*
FROM
query_one
LEFT JOIN query_two USING (mon, yyyy)
ORDER BY
yyyy
, mon;
USING
子句更易于使用,可以防止mon
和yyyy
在输出中出现两次,其余的只是为了清晰地查看。两个表中是否都有一列可以相互链接?@AndreasSchmidt没有,我想你的选项是最好的,它工作得很好,谢谢!因为在其他情况下是的,我们需要删除重复的列,然后对空日期使用COALESCE和NULLIF