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sql server潜在客户-日期问题_Sql_Sql Server_Date_Lead - Fatal编程技术网

sql server潜在客户-日期问题

sql server潜在客户-日期问题,sql,sql-server,date,lead,Sql,Sql Server,Date,Lead,我发现sql server 2012中新的lead olap函数存在问题 CREATE TABLE Atext (id int, bez varchar(10), von date); GO INSERT INTO Atext VALUES (1, 't1', '2001-01-01'), (1, 't2', '2012-01-01'), (2, 'a1', '2020-01-01'), (2,'a1' , '2030-01-01'), (2, 'b', '2040-05-01'), (2

我发现sql server 2012中新的lead olap函数存在问题

CREATE TABLE Atext (id int, bez varchar(10), von date); 

GO

INSERT INTO Atext VALUES (1, 't1', '2001-01-01'), (1, 't2', '2012-01-01'), (2, 'a1', '2020-01-01'), (2,'a1' , '2030-01-01'), (2, 'b', '2040-05-01'), (2, 'a3', '2989-05-01'); 
GO

SELECT 
        id, 
        bez, 
        von,
        lead(von,1,0) over (partition by id ORDER BY von) -1 as bis
FROM 
        Atext
order by 
        id, 
        Von
select查询引发错误:

Msg 206, Level 16, State 2, Line 1 
Operand type clash: int is incompatible with date
为什么在数据类型datetime方面存在限制

我知道一个解决方法,但不是很好:

SELECT
    id,
    bez,
    CAST(vonChar AS DATE) AS Von,
    CASE
        WHEN bisChar <> '0'
        THEN (DATEADD(DAY,-1,(CAST((
                    CASE
                        WHEN bisChar <> '0'
                        THEN vonChar
                        ELSE NULL
                    END)AS DATE)) ))
        ELSE NULL /*'9999-12-31'*/
    END AS Bis
FROM
    (
        SELECT
            id,
            bez,
            vonChar ,
            lead(vonChar,1,0) over (partition BY id ORDER BY vonChar) AS bisChar
        FROM
            (
                SELECT
                    id,
                    bez,
                    CAST(von AS VARCHAR(10)) vonChar
                FROM
                    Atext) tab ) tab2
ORDER BY
    id,
    Von

Microsoft SQL Server 2012 SP1-11.0.3128.0 X64

使用日期或可以隐式转换为日期的内容作为lead函数的默认值,DATEADD函数将是一个更简单的解决方法:

SELECT 
        id, 
        bez, 
        von,
        DATEADD(DAY, -1, LEAD(von, 1, '19000101') 
                        OVER (PARTITION BY id ORDER BY von)) AS bis
FROM Atext
ORDER BY id, Von;
或者干脆不用担心违约。不需要:

SELECT 
        id, 
        bez, 
        von,
        DATEADD(DAY, -1, LEAD(von, 1) 
                        OVER (PARTITION BY id ORDER BY von)) AS bis
FROM Atext
ORDER BY id, Von;
问题是不能将INT转换为日期。在SQL Server中的表达式中,表达式的所有部分都必须具有相同的数据类型,因此,如果您这样做,例如:

SELECT TOP 1 GETDATE() + number
FROM master..spt_values
WHERE type = 'p'
后台SQL Server需要决定是将GETDATE转换为整数,以便表达式的所有部分都是整数,还是将1转换为datetime,以便 所有部分都是日期时间。SQL Server规定DATETIME的优先级高于INT,因此SQL Server将1转换为DATETIME,这可以在执行计划中看到:

<ScalarOperator ScalarString="getdate()+[Expr1005]">
....
<ColumnReference Column="Expr1005" />
<ScalarOperator ScalarString="CONVERT_IMPLICIT(datetime,[master].[dbo].[spt_values].[number],0)">
这表明INT列master..spt_values.number在添加到getdate之前隐式转换为datetime


无论出于何种原因,我不久前进行了广泛的研究,没有找到任何确切的解释,因为没有从int到date的隐式或显式转换,您必须使用date函数。

您可以在这个查询中使用DATEADD。此外,数据类型的LEAD的默认值不能为0,因此我已将其更改为NULL,或者您可以使用任何日期常量

SELECT 
        id, 
        bez, 
        von,
        DATEADD(DAY,-1,lead(von,1,NULL) 
                       over (partition by id ORDER BY von)) as bis
FROM 
        Atext
order by 
        id, 
        Von

这将对您有所帮助,错误发生在指定了0而不是预期的日期字段时

I replaced lead(von,1,0) with lead(von,1,'1900-01-01')
查看具有相同结果的其他代码

SET DATEFORMAT ymd
DECLARE @Atext TABLE  
    (id INT, bez VARCHAR(10), von DATE); 

INSERT INTO @Atext VALUES 
    (1, 't1', '2001-01-01'),
    (1, 't2', '2012-01-01'), (2, 'a1', '2020-01-01'), 
    (2,'a1' , '2030-01-01'), (2, 'b', '2040-05-01'),
    (2, 'a3', '2099-05-01'); 

SELECT  id, 
        bez, 
        von,
        lead(von,1,'1900-01-01') OVER (PARTITION BY id ORDER BY von) AS bis
FROM    @Atext
ORDER   by 
        id, 
        Von
结果


与所有其他答案相同,但以DATEADD作为lead的参数:

SELECT
  id, 
  bez,
  von,
  lead(DATEADD(DAY,-1, von),1, null) over (partition by id order by von)
from 
  Atext
order by
    id,
    Von
范例