Sql ut.我不确定这是否有效…你如何获得stage+1？这似乎得到了阶段之间的间隔…即//阶段1（B）-阶段1（A）。我想问题是如何获得阶段之间的差异（即//stage 2-stage 1）。实际上，这个查询还将为您提供stage 3 stage 1 150。
Sql ut.我不确定这是否有效…你如何获得stage+1？这似乎得到了阶段之间的间隔…即//阶段1（B）-阶段1（A）。我想问题是如何获得阶段之间的差异（即//stage 2-stage 1）。实际上，这个查询还将为您提供stage 3 stage 1 150。,sql,average,Sql,Average,ut.我不确定这是否有效…你如何获得stage+1？这似乎得到了阶段之间的间隔…即//阶段1（B）-阶段1（A）。我想问题是如何获得阶段之间的差异（即//stage 2-stage 1）。实际上，这个查询还将为您提供stage 3 stage 1 150。从需求中不清楚这是否是需要的。我认为不是。谢谢你对我的解决方案发表评论，然后把它偷来声称是你自己的，甚至没有投票给我…@David:Vilx的代码与你的不同（例如，你不使用group by），更好地呈现和解释了。@APC:作者没有指定如何区分哪
ut.我不确定这是否有效…你如何获得stage+1？这似乎得到了阶段之间的间隔…即//阶段1（B）-阶段1（A）。我想问题是如何获得阶段之间的差异（即//stage 2-stage 1）。实际上，这个查询还将为您提供
stage 3 stage 1 150event Name | Time
stage 1 | 10:01
stage 2 | 10:03
stage 3 | 10:06
stage 1 | 10:10
stage 2 | 10:15
stage 3 | 10:21
stage 1 | 10:22
stage 2 | 10:23
stage 3 | 10:29
(3+6+6)/3 = 5
Select Avg(e.Time - s.Time)
From Table s
Join Table e
On e.Time =
(Select Min(Time)
From Table
Where eventname = s.eventname
And time > s.Time)
And Not Exists
(Select * From Table
Where eventname = s.eventname
And time < s.Time)
Select s.EventName,
s.Time Startime, e.Time EndTime,
(e.Time - s.Time) Elapsed
From Table s
Join Table e
On e.Time =
(Select Min(Time)
From Table
Where eventname = s.eventname
And time > s.Time)
And Not Exists
(Select * From Table
Where eventname = s.eventname
And time < s.Time)
WITH q AS
(
SELECT 'stage 1' AS eventname, CAST('2009-01-01 10:01:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 2' AS eventname, CAST('2009-01-01 10:03:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 3' AS eventname, CAST('2009-01-01 10:06:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 1' AS eventname, CAST('2009-01-01 10:10:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 2' AS eventname, CAST('2009-01-01 10:15:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 3' AS eventname, CAST('2009-01-01 10:21:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 1' AS eventname, CAST('2009-01-01 10:22:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 2' AS eventname, CAST('2009-01-01 10:23:00' AS DATETIME) AS eventtime
UNION ALL
SELECT 'stage 3' AS eventname, CAST('2009-01-01 10:29:00' AS DATETIME) AS eventtime
)
SELECT (
SELECT AVG(DATEDIFF(minute, '2009-01-01', eventtime))
FROM q
WHERE eventname = 'stage 3'
) -
(
SELECT AVG(DATEDIFF(minute, '2009-01-01', eventtime))
FROM q
WHERE eventname = 'stage 2'
)
Select Avg(differ) from (
Select s1.r, s2.r, s2.time - s1.time as differ from (
Select * From (Select rownum as r, inn.time from table inn order by time) s1
Join (Select rownum as r, inn.time from table inn order by time) s2
On mod(s2.r, 3) = 2 and s2.r = s1.r + 1
Where mod(s1.r, 3) = 1)
);
select a.eventName, b.eventName, AVG(DATEDIFF(MINUTE, a.[Time], b.[Time])) as Average from
(select *, row_number() over (order by [time]) rn from events) a
join (select *, row_number() over (order by [time]) rn from events) b on (a.rn=b.rn-1)
group by
a.eventName, b.eventName
stage3 stage1 2
stage1 stage2 2
stage2 stage3 5
event Name | Time
stage 1 | 10:01
stage 2 | 10:03
stage 3 | 10:06
stage 1 | 10:10
stage 2 | 10:15
stage 3 | 10:21
stage 1 | 10:22
stage 2 | 10:23
stage 1 | 10:25 --- new stage 1
stage 2 | 10:28 --- new stage 2
stage 3 | 10:29
stage 3 | 10:34 --- new stage 3
SQL> select stage_range
2 , avg(time_diff)/60 as average_time_diff_in_min
3 from
4 (
5 select event_name
6 , case when event_name = 'stage 2' then 'stage 1 to 2'
7 when event_name = 'stage 3' then 'stage 2 to 3'
8 else '!!!' end as stage_range
9 , stage_secs - lag(stage_secs)
10 over (order by ts, event_name) as time_diff
11 from
12 ( select event_name
13 , ts
14 , to_number(to_char(ts, 'sssss')) as stage_secs
15 from timings )
16 )
17 where event_name in ('stage 2','stage 3')
18 group by stage_range
19 /
STAGE_RANGE AVERAGE_TIME_DIFF_IN_MIN
------------ ------------------------
stage 1 to 2 2.66666667
stage 2 to 3 5
SQL>