来自2个表的SQLite比较查询

我想创建一个新的查询，以了解商店中有多少产品

表：tb_商店

    +--------+------------+------------------+-----------+
    | item_id| nome       |  data_out        |   data_in |
    +--------+------------+------------------+-----------+
    | 1      | Produ1     | null             | 2015-01-06|
    | 2      | Produ1     | null             | 2015-01-06|
    | 3      | Produ3     | null             | 2015-01-06|
    | 4      | Produ3     | null             | 2015-01-06|
    | 5      | Produ5     | null             | 2015-01-06|
    | 6      | Produ4     | 2015-01-06       | 2015-02-06|
    | 7      | Produ2     | 2015-01-06       | 2015-02-06|
    +--------+------------+------------------+-----------+

表：tb\U产品

+--------+------------+
| item_id| nome       |
+--------+------------+
| 1      | Produ1     |
| 2      | Produ2     |
| 3      | Produ3     |
| 4      | Produ4     |
| 5      | Produ5     |
+--------+------------+

我写了这个问题：

select nome, count(nome) as pezzi from  tb_store where data_out is null or data_out="" group by nome order by pezzi desc

结果是：

+--------+------------+
| nome   | pezzi      |
+--------+------------+
| Produ1 | 2          |
| Produ3 | 2          |
| Produ5 | 1          |
+--------+------------+

我想得到这个结果：

+--------+------------+
| nome   | pezzi      |
+--------+------------+
| Produ1 | 2          |
| Produ3 | 2          |
| Produ5 | 1          |
| Produ2 | 0          |
| Produ4 | 0          |
+--------+------------+

有可能吗？如何重写查询

编辑

我创建了一个新查询，如下所示：

    SELECT DISTINCT nome, pezzi FROM(
SELECT nome,COALESCE(pezzi,0)as pezzi FROM(
SELECT p.nome, COUNT(s.nome) as pezzi
FROM tb_product as p LEFT JOIN tb_store as s
ON   p.nome = s.nome
WHERE s.data_out is null
OR    s.data_out = ""
GROUP BY p.nome
union
select nome,null as pezzi from tb_product) )
ORDER BY pezzi DESC

但是我有一些重复的项目要删除…结果是

nome         pezzi
crema         2
pistacchio    2
zabajone      2
bacio         1
cassata       1
cioccolato    1
ciocco rum    1
malaga        1
mango         1
mascarpone    1
nocciola      1
stracciatella 1
bacio         0
caramello     0
cassata       0
cioccolato    0
ciocco rum    0
crema         0
fragola       0
limone        0
malaga        0
mango         0
mascarpone    0
nocciola      0
pistacchio    0
zabajone      0

是否可以删除0的副本

SELECT DISTINCT nome, pezzi FROM(
SELECT nome,COALESCE(pezzi,0)as pezzi FROM(
SELECT p.nome, COUNT(s.nome) as pezzi
FROM tb_product as p LEFT JOIN tb_store as s
ON   p.nome = s.nome
WHERE s.data_out is null
OR    s.data_out = ""
GROUP BY p.nome
union
select nome,null as pezzi from tb_product) GROUP BY nome ) 
ORDER BY pezzi DESC

---

您需要在两个表之间执行左联接，如：

SELECT p.nome, COUNT(s.nome) as pezzi
FROM tb_product as p LEFT JOIN tb_store as s
ON   p.name = s.name
WHERE data_out is null
OR    data_out = ""
GROUP BY p.nome
ORDER BY pezzi DESC

---

我已经尝试在Sqlite的DB Browser上模拟查询，结果是：没有这样的列：date\u out：选择p.nome，将（s.nome）计数为来自tb\u产品p的pezzi LEFT JOIN tb\u store s on p.name=s.name，其中date\u out为null或date\u out=“”按p.nome分组按pezzi Desce排序以上在您的帖子中，您向我们展示了您的日期字段，现在您发现了错误？请检查确切的名称好吗？好的，查询运行，但只显示数据>0，不显示数据=0。我已经发布了文件（mycpstore.db）。例如：更新表，但我认为问题在于where条件，可能我需要在两个不同的查询中创建apped od数据，因为where表示数据为null或空。那你现在在看什么？