String 在Tex数中转换Tex字符串

在需要数值的参数中使用自动生成的Tex字符串时出现问题（例如，在ifthenelse比较中）。下面是一个示例代码：

\newcommand\testC{123}
\ifthenelse{\testC<0}{negative}{positive} % works fine !

\newcommand{\testD}{\luaexec{tex.write("123")}} % write to avoid the print carriage return - produces also 123 as \testC
\testD % prompt 132 just as \testC "apparently"
\ifthenelse{\testD<0}{negative}{positive} % error "! Missing number, treated as zero"

\newcounter{compteur}
\setcounter{compteur}{\testD} % error "! Missing number, treated as zero"
\ifthenelse{\thecompteur<0}{negative}{positive}

\newcommand\testC{123}
\如果{\testC注意，
\luaexec
（requires
\usepackage{luacode}
）不可扩展，因此它不能用于（Lua）TeX在扩展后需要
的地方

\documentclass{article}
\usepackage{luacode}
\usepackage{ifthen}

\begin{document}

\newcommand\testC{123}
\ifthenelse{\testC<0}{negative}{positive} % works fine !

\newcommand{\testD}{\directlua{tex.sprint("123")}} % write to avoid the print carriage return - p$

\testD % prompt 132 just as \testC "apparently"

\ifthenelse{\testD<0}{negative}{positive} % error "! Missing number, treated as zero"

\newcounter{compteur}
\setcounter{compteur}{\testD} % error "! Missing number, treated as zero"
\ifthenelse{\value{compteur}<0}{negative}{positive}

\end{document}

\documentclass{article}
\usepackage{luacode}
\使用包{ifthen}
\开始{document}
\纽科曼\testC{123}
\如果其他{\testC