Swift 将指针元组强制转换为指针的指针

我有一段C代码：

#define AV_NUM_DATA_POINTERS 8
uint8_t *data[AV_NUM_DATA_POINTERS];

在swift生成的界面中，如下所示：

var data: (UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?)

但是，swift提供以下签名：

func sws_scale(..., _ srcSlice: UnsafePointer<UnsafePointer<UInt8>?>!, ...) -> Int32

func sws\u scale（…，\srcsicle:UnsafePointer！，…）->Int32

将巨大的元组转换为适用于

sws\u scale

函数的类型的最佳方法是什么？

示例来自：

应用于

sws\u标度

：

var data: (UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?)
withUnsafePointer(to: data) { dataPointer in
   let dataPointer =
      UnsafeRawPointer(dataPointer)
         .assumingMemoryBound(to: UnsafePointer<UInt8>?.self)

   sws_scale(…, dataPointer, …)
}

在优化构建中使用上述内容时，我遇到了内存对齐问题。

这可能会有所帮助：

var bytes: (CChar, CChar, CChar, CChar) = (0x61, 0x62, 0x63, 0)
let name: String = withUnsafePointer(to: &bytes) { ptr -> String in
   return String(cString: UnsafeRawPointer(ptr).assumingMemoryBound(to: CChar.self))
}

var data: (UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?, UnsafeMutablePointer<UInt8>?)
withUnsafePointer(to: data) { dataPointer in
   let dataPointer =
      UnsafeRawPointer(dataPointer)
         .assumingMemoryBound(to: UnsafePointer<UInt8>?.self)

   sws_scale(…, dataPointer, …)
}

withUnsafePointer(to: &data.0)