Swift 在两个字符串之间快速获取字符串

我有以下字符串：

"Notes[9219:1224244] [BoringSSL] Function boringssl_context_get_peer_sct_list: line 1757 received sct extension length is less than sct data length [[["encendedor","lighter",null,null,1]],null,"en"]"

我只想提取引号第一次出现之间的字符串，在本例中是“encendedor”。 我尝试了下面的代码，我从

我当前遇到以下错误：

Thread 6: Fatal error: 'try!' expression unexpectedly raised an error: Error Domain=NSCocoaErrorDomain Code=2048 "The value “[[[(.*?),” is invalid." UserInfo={NSInvalidValue=[[[(.*?),}

如何正确提取此字符串？谢谢你的帮助

使用

组件（分隔符：）

：

---

您还可以使用range在两个字符串之间进行切片

extension String {

    func slice(from: String, to: String) -> String? {

        return (range(of: from)?.upperBound).flatMap { substringFrom in
            (range(of: to, range: substringFrom..<endIndex)?.lowerBound).map { substringTo in
                String(self[substringFrom..<substringTo])
            }
        }
    }
}

let slicedString = yourString.slice(from: "\"", to: "\"") // Optional("encendedor")

扩展字符串{
func切片（from:String，to:String）->String{
return（范围：from）？.upperBound.flatMap{substringFrom in
（range（of:to，range:substringFrom..各种解决方案（带和不带regex）at.正则表达式需要对所有
[
进行转义。
*？
也没有意义
var str = "Notes[9219:1224244] [BoringSSL] Function boringssl_context_get_peer_sct_list: line 1757 received sct extension length is less than sct data length [[[\"encendedor\",\"lighter\",null,null,1]],null,\"en\"]"

str.components(separatedBy: "\"")[1] // "encendedor"

extension String {

    func slice(from: String, to: String) -> String? {

        return (range(of: from)?.upperBound).flatMap { substringFrom in
            (range(of: to, range: substringFrom..<endIndex)?.lowerBound).map { substringTo in
                String(self[substringFrom..<substringTo])
            }
        }
    }
}

let slicedString = yourString.slice(from: "\"", to: "\"") // Optional("encendedor")