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Swift URL请求中出现错误";操作无法’;不可能完成。没有这样的文件或目录;_Swift_Api_Http Post_Strongloop_Loopback - Fatal编程技术网

Swift URL请求中出现错误";操作无法’;不可能完成。没有这样的文件或目录;

Swift URL请求中出现错误";操作无法’;不可能完成。没有这样的文件或目录;,swift,api,http-post,strongloop,loopback,Swift,Api,Http Post,Strongloop,Loopback,自从更新到9.1之后,URL请求的Swift语法发生了变化,我一直在向API发出请求时出错。例如,此POST请求只是尝试登录。我可以直接在API(Strongloop Loopback)浏览器界面登录,但不能从Swift登录。我得到这个错误: 无法完成该操作。没有此类文件或目录 我的代码是这样的: func performLoginRequestWithURL(url: NSURL, email: String, password: String) { let bodyD

自从更新到9.1之后,URL请求的Swift语法发生了变化,我一直在向API发出请求时出错。例如,此POST请求只是尝试登录。我可以直接在API(Strongloop Loopback)浏览器界面登录,但不能从Swift登录。我得到这个错误:

无法完成该操作。没有此类文件或目录

我的代码是这样的:

func performLoginRequestWithURL(url: NSURL, email: String, password: String) {
            let bodyData = "email=\(email)&password=\(password)"
            let request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
            let session = NSURLSession.sharedSession()
            request.HTTPMethod = "POST"
            request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding)

            let task = session.dataTaskWithRequest(request, completionHandler: {
                data, response, error -> Void in
                if let error = error {
                    let errString = error.localizedDescription
                    NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": errString])
                    print(error.localizedDescription)

                } else if data != nil {
                    let json = NSString(data: data!, encoding: NSUTF8StringEncoding) as! String

                    if let dictionary = JSON().parseJSON(json) as [String: AnyObject]? {
                        let accesstoken = dictionary["id"] as! String
                        let id = dictionary["userId"] as! Int

                        // MARK: - Store UID & AccessToken
                        NSUserDefaults.standardUserDefaults().setBool(true, forKey: "userLoggedIn")
                        NSUserDefaults.standardUserDefaults().setInteger(id, forKey: "userId")
                        NSUserDefaults.standardUserDefaults().setObject(accesstoken, forKey: "accessToken")
                        NSUserDefaults.standardUserDefaults().synchronize()
                        NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": "Success"])
                    }
                }

            })
            task.resume()
        }
下面是它工作时的样子,但他们贬低了sendAsynchronousRequest方法:

func performLoginRequestWithURL(url: NSURL, email: String, password: String) {
        let bodyData = "email=\(email)&password=\(password)"
        var request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
        request.HTTPMethod = "POST"
        request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding)
        NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()){
            response, data, error in

            if let error = error {
                let errString = error.localizedDescription
                NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": errString])

            } else if data != nil {
                let json = NSString(data: data, encoding: NSUTF8StringEncoding) as! String

                if let dictionary = JSON().parseJSON(json) as [String: AnyObject]? {
                    let accesstoken = dictionary["id"] as! String
                    let id = dictionary["userId"] as! Int
                    var results = [String: AnyObject]()
                    results = ["at": accesstoken, "id": id]

                    // MARK: - Store UID & AccessToken
                    NSUserDefaults.standardUserDefaults().setBool(true, forKey: "userLoggedIn")
                    NSUserDefaults.standardUserDefaults().setInteger(id, forKey: "userId")
                    NSUserDefaults.standardUserDefaults().setObject(accesstoken, forKey: "accessToken")
                    NSUserDefaults.standardUserDefaults().synchronize()
                    NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": "Success"])
                }
            }

        }
    }

事实证明,这个问题与新语法无关,与ios9以及从模拟器向localhost发出请求的方式有关。我能够向我的本地IP 10.x.x.2发出请求,但这不再有效,我必须使用127.0.0.1。这将使通过电话连接变得困难。我现在每次都要换IP