Swift URL请求中出现错误";操作无法’;不可能完成。没有这样的文件或目录;
自从更新到9.1之后,URL请求的Swift语法发生了变化,我一直在向API发出请求时出错。例如,此POST请求只是尝试登录。我可以直接在API(Strongloop Loopback)浏览器界面登录,但不能从Swift登录。我得到这个错误:Swift URL请求中出现错误";操作无法’;不可能完成。没有这样的文件或目录;,swift,api,http-post,strongloop,loopback,Swift,Api,Http Post,Strongloop,Loopback,自从更新到9.1之后,URL请求的Swift语法发生了变化,我一直在向API发出请求时出错。例如,此POST请求只是尝试登录。我可以直接在API(Strongloop Loopback)浏览器界面登录,但不能从Swift登录。我得到这个错误: 无法完成该操作。没有此类文件或目录 我的代码是这样的: func performLoginRequestWithURL(url: NSURL, email: String, password: String) { let bodyD
无法完成该操作。没有此类文件或目录
我的代码是这样的:
func performLoginRequestWithURL(url: NSURL, email: String, password: String) {
let bodyData = "email=\(email)&password=\(password)"
let request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
let session = NSURLSession.sharedSession()
request.HTTPMethod = "POST"
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding)
let task = session.dataTaskWithRequest(request, completionHandler: {
data, response, error -> Void in
if let error = error {
let errString = error.localizedDescription
NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": errString])
print(error.localizedDescription)
} else if data != nil {
let json = NSString(data: data!, encoding: NSUTF8StringEncoding) as! String
if let dictionary = JSON().parseJSON(json) as [String: AnyObject]? {
let accesstoken = dictionary["id"] as! String
let id = dictionary["userId"] as! Int
// MARK: - Store UID & AccessToken
NSUserDefaults.standardUserDefaults().setBool(true, forKey: "userLoggedIn")
NSUserDefaults.standardUserDefaults().setInteger(id, forKey: "userId")
NSUserDefaults.standardUserDefaults().setObject(accesstoken, forKey: "accessToken")
NSUserDefaults.standardUserDefaults().synchronize()
NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": "Success"])
}
}
})
task.resume()
}
下面是它工作时的样子,但他们贬低了sendAsynchronousRequest方法:
func performLoginRequestWithURL(url: NSURL, email: String, password: String) {
let bodyData = "email=\(email)&password=\(password)"
var request: NSMutableURLRequest = NSMutableURLRequest(URL: url)
request.HTTPMethod = "POST"
request.HTTPBody = bodyData.dataUsingEncoding(NSUTF8StringEncoding)
NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue.mainQueue()){
response, data, error in
if let error = error {
let errString = error.localizedDescription
NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": errString])
} else if data != nil {
let json = NSString(data: data, encoding: NSUTF8StringEncoding) as! String
if let dictionary = JSON().parseJSON(json) as [String: AnyObject]? {
let accesstoken = dictionary["id"] as! String
let id = dictionary["userId"] as! Int
var results = [String: AnyObject]()
results = ["at": accesstoken, "id": id]
// MARK: - Store UID & AccessToken
NSUserDefaults.standardUserDefaults().setBool(true, forKey: "userLoggedIn")
NSUserDefaults.standardUserDefaults().setInteger(id, forKey: "userId")
NSUserDefaults.standardUserDefaults().setObject(accesstoken, forKey: "accessToken")
NSUserDefaults.standardUserDefaults().synchronize()
NSNotificationCenter.defaultCenter().postNotificationName(self.lh, object: nil, userInfo: ["Result": "Success"])
}
}
}
}
事实证明,这个问题与新语法无关,与ios9以及从模拟器向localhost发出请求的方式有关。我能够向我的本地IP 10.x.x.2发出请求,但这不再有效,我必须使用127.0.0.1。这将使通过电话连接变得困难。我现在每次都要换IP