Swift 阿拉莫菲尔斯威夫特转换

嗨，我想向API发出请求，但当发送时，控制台会显示给我

无效URL

---

Alamofire.request（“https://.../api/v1.8/set/order/?address=\（地址）&email=\（电子邮件）&information=\（信息）&name=\（名称）&order=\（参数）&password=\（密码）&paymentType=\（支付类型）&phone=\（电话）&token=\（令牌）&userID=\（userID）&wihtRegistration=\（wihtRegistration）”。验证（状态代码：200..我创建了这个自定义方法。通过传递所需参数调用它：-

没有JSON编码

func requestWithoutJSONEncoding(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}

func request(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, encoding: JSONEncoding.default, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}

使用JSON编码

func requestWithoutJSONEncoding(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}

func request(_ method: HTTPMethod
    , _ URLString: String
    , parameters: [String : AnyObject]? = [:]
    , headers: [String : String]? = [:]
    , completion:@escaping (Any?) -> Void
    , failure: @escaping (Error?) -> Void) {

    Alamofire.request(URLString, method: method, parameters: parameters, encoding: JSONEncoding.default, headers: headers)
        .responseJSON { response in

            switch response.result {
            case .success:
                completion(response.result.value!)
            case .failure(let error):
                failure(error)
            }
    }
}

试试这个

 let jsonObject = [["code": 404, "counts": 15]]

    let json = JSON(jsonObject)

    // Generate the string representation of the JSON value
    let jsonString = json.rawString(.utf8)!
    let params = ["name": name, "phone": phone, "address": address, "information": information, "email": email, "userID":userID, "wihtRegistration": wihtRegistration, "password": password, "token": token, "paymentType": paymentType, "order" : jsonString] as [String : Any]

    Alamofire.request("http:...", method: .get, parameters: params)
        .responseString { response in
            #if DEBUG
(request!.url!.absoluteString)\n\(request!.httpBody.map { body in String(data: body, encoding: .utf8) ?? "" } ?? "")")
            switch response.result {
            case .success(let value):
                print("Response with content \(value)")
            case .failure(let error):
                print("Response with error: \(error as NSError): \(response.data ?? Data())")
            }
            #endif
    }

“转换”是什么意思？我认为“invalidURL”错误很明显，您应该检查“https://.../api/v1.8/set/order/?address=（地址）&email=（电子邮件）&information=（信息）&name=（名称）&order=（参数）&password=（密码）&paymentType=（paymentType）&phone=（电话）&token=（令牌）&userID=（userID）&wihtRegistration=（wihtRegistration）”“address=（address）”：如果它有空格，它可能会失败。另外，为什么不使用那里的参数为您执行此操作？如果没有空格，我需要为order请求[{:}]，如果您执行
let url=url（string:yourString）
is
url
not
nil
？不，我传递
Alamofire.request（”https://..“”