Swift 不与随机CG点相交

我有方法生成随机位置我的UIImageView。某些视图与其他视图相交。我怎么检查这个十字路口？可能在某个数组中写入位置？类似这样的事情-

    self.randomArray.append(random)

    for views in randomArray {

        let rangeXmin = views.x - widthCoin / 2
        let rangeXmax = views.x + widthCoin / 2
        let rangeYmin = views.y - widthCoin / 2
        let rangeYmax = views.y + widthCoin / 2
        let rangeX = rangeXmin...rangeXmax
        let rangeY = rangeYmin...rangeYmax

        if rangeX.contains(randomX) || rangeY.contains(randomY) {
           print("Intersection")
        } else {
            print("Not intersection")
        }
     }

// generate coin place in table

func generateCoinPlace() -> CGPoint {

    let widthTableConstant = view.frame.width * 0.89
    let heightTableConstant = widthTableConstant * 1.04

    let minX = view.center.x - widthTableConstant / 2 + widthCoin / 4
    let maxX = view.center.x + widthTableConstant / 2 - widthCoin / 4
    let minY = tableImage.center.y - heightTableConstant / 2 + widthCoin / 4
    let maxY = tableImage.center.y + heightTableConstant / 2 - widthCoin / 4

    let randomX = CGFloat.random(in: minX..<maxX)
    let randomY = CGFloat.random(in: minY..<maxY)
    let random = CGPoint(x: randomX, y: randomY)

      // Add array here

    return random
}

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谢谢你的帮助。

你可以试试这个条件

(rangeX.contains(randomX - widthCoin / 2) || rangeX.contains(randomX + widthCoin / 2)) && (rangeY.contains(randomY - widthCoin / 2) || rangeY.contains(randomY + widthCoin / 2))

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是的，randomX只是点，randomX-widthCoin/2和randomX+widthCoin/2给出了视图大小。谢谢，我正在努力。

(rangeX.contains(randomX - widthCoin / 2) || rangeX.contains(randomX + widthCoin / 2)) && (rangeY.contains(randomY - widthCoin / 2) || rangeY.contains(randomY + widthCoin / 2))