Swift 解析查询不匹配点pfuser

我已经开发了一个朋友关系应用程序，用户可以添加存在的用户作为朋友。 然后我在做一个搜索朋友函数，我的表结构如下： PFUser-->记录当前用户（标准类） 好友列表-->用户名（我的用户名），好友（PFUser的点数）

当用户添加关系时：

        var friendListObject = PFObject(className: "FriendList")
        friendListObject.setObject(currentUser!.username!, forKey: "myusername")
        friendListObject.setObject(result.user, forKey: "friend") //result.user = PFUser
        friendListObject.saveInBackgroundWithBlock{
            (success: Bool, error: NSError?) -> Void in
            if (success) {

            }
        }

当我想搜索新朋友时，那朋友在我的关系中没有，我有使用下面的代码，但是，不起作用。你有什么建议吗

    var resultQuery = PFQuery(className: "FriendList")
    resultQuery.whereKey("myusername", equalTo: currentUser!.username!)
    resultQuery.selectKeys(["friend"])

    var query = PFUser.query()

    query!.whereKey("username", notEqualTo: currentUser!.username!)
    query!.whereKey("objectId", doesNotMatchKey: "friend", inQuery: resultQuery)

    query!.findObjectsInBackgroundWithBlock {
        (objects: [AnyObject]?, error: NSError?) -> Void in
    }

---

在添加额外字段“friendusername”以保留PFUser.currentUser（）.username时，我修改了代码

搜索时，使用doesnotmatch的friendusername，这样就可以了

var resultQuery = PFQuery(className: "FriendList")
resultQuery.whereKey("myusername", equalTo: currentUser!.username!)
resultQuery.selectKeys(["friend"])

var query = PFUser.query()

query!.whereKey("username", notEqualTo: currentUser!.username!)
query!.whereKey("objectId", doesNotMatchKey: "friend", inQuery: resultQuery)

query!.findObjectsInBackgroundWithBlock {
    (objects: [AnyObject]?, error: NSError?) -> Void in
}

var resultQuery = PFQuery(className: "FriendList")
resultQuery.whereKey("myusername", equalTo: currentUser!.username!)
resultQuery.selectKeys(["friend"])

var query = PFUser.query()

query!.whereKey("username", notEqualTo: currentUser!.username!)
query!.whereKey("objectId", doesNotMatchKey: "friend", inQuery: resultQuery)

query!.findObjectsInBackgroundWithBlock {
    (objects: [AnyObject]?, error: NSError?) -> Void in
}