Swift3 代码错误，使用了未声明的类型

我有这个错误 我能做些什么来修复它。下面是错误代码

@IBAction func btnActionShowViewController(_ sender: Any) {

    let view1:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: //error is here
"StoryboardIdOfview1") as? view1

    self.navigationController?.pushViewController(view1, animated: true)

}

这是我的全部代码

//
//  ViewController.swift
//  app21
//
//  Created by Jared Evan Miller on 8/14/17.
//  Copyright © 2017 Jared Evan Miller. All rights reserved.
//

import UIKit
import AVFoundation

class ViewController: UIViewController {
// sounds are showed here
let soundFilenames = ["5","8","7","4","6","1","3","2","9"]
var audioPlayers = [AVAudioPlayer]()
// stop button and play from begginning
var lastAudioPlayer = 0
// back to code
var audioPlayer = AVAudioPlayer()
override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.

// set up audio players
   for sound in soundFilenames{
        do {

            let url = URL(fileURLWithPath: Bundle.main.path(forResource: sound, ofType: "wav")!);
            let audioPlayer = try AVAudioPlayer(contentsOf:url)

            audioPlayers.append(audioPlayer)
        }
        catch {

            // Catch the error that is thrown
            audioPlayers.append(AVAudioPlayer())


        }
               }

  }

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.



// IBAction section ( always goes in between the last and second to last bracket } (  IBAction would go here)     }




}

@IBAction func buttonTapped(_ sender: UIButton) {

// Get the audioPlayer that corresponds to the button that they tapped
// middle buttons
    let lastPlayer = audioPlayers[lastAudioPlayer]
    lastPlayer.stop();
    lastAudioPlayer = sender.tag;
    lastPlayer.currentTime = 0;
    audioPlayer = audioPlayers[sender.tag]
    audioPlayer.currentTime = 0;
    audioPlayer.play()
}
// side buttons
@IBAction func buttonTapped2(_ sender: UIButton) {
    let lastPlayer = audioPlayers[lastAudioPlayer]
    lastPlayer.stop();
    lastAudioPlayer = sender.tag;
    lastPlayer.currentTime = 0;
    audioPlayer = audioPlayers[sender.tag]
    audioPlayer.currentTime = 0;
    audioPlayer.play()
}
// This Action allows users to stop the audio
// stop audio button
@IBAction func stop(_ sender: UIButton) {
    if audioPlayer.isPlaying {
        audioPlayer.stop()
   }
}

这是我有一个按钮，一次有两个动作，我想第一个播放音乐，第二个显示另一个名为view1的视图控制器。谢谢

@IBAction func btnActionPlayMusic(_ sender: Any) {


}





@IBAction func btnActionShowViewController(_ sender: Any) {

    let view1:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: //error is here
"StoryboardIdOfview1") as? view1

    self.navigationController?.pushViewController(view1, animated: true)

}





}

---

我相信你投错了destinationViewController。。。。作为？ 视图1可能不正确。您的代码：

let view1:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: //error is here
"StoryboardIdOfview1") as? view1

你应该这样做：

let view1:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: //error is here
"StoryboardIdOfview1") as! view1UIViewController

其中，View1IViewController是在identity inspector中定义的视图控制器的自定义类，如下所示：

==编辑=== 根据您的评论，问题代码行应为：

let view1:UIViewController =  self.storyboard?.instantiateViewController(withIdentifier: //error is here
"StoryboardIdOfview1") as? UIViewController

---

您正在将某个对象强制转换为一个变量，并将返回值赋给该变量。。。这是如何工作的？我只是在网上找到了它，今天复制并粘贴了它。我不知道真正的代码。我想让这些代码做的是转到另一个名为View1的视图控制器。问题是你的演员阵容。删除as？视图1。这是不需要的，因为函数返回变量所属的对象类型。如果有什么需要的话，你可以把它转换成UIViewController。你能给我发个代码吗？我不知道。我有view1作为情节提要，我也没有两个view controller。Swift东西只有一个，只有两个情节提要这还不够Jared。它标识要转到的目标控制器，但必须正确指定其类型。view1只是一个UIViewController或自定义UIViewController。如果是后者，您必须在上面的图像中准确地指定您拥有的内容。如果不是自定义的，则不指定名称，而是指定其类类型。。。你是什么意思