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Symfony2构造本月_Symfony_Datetime - Fatal编程技术网

Symfony2构造本月

Symfony2构造本月,symfony,datetime,Symfony,Datetime,我正在尝试设置当前月份。我试过: /** * @var \DateTime * * @ORM\Column(name="act_month", type="datetime") */ private $actMonth; public function __construct() { $date = \DateTime::createFromFormat('M', 'now'); $this->actMonth = $date; } 错误:在boolean上调用成员函数

我正在尝试设置当前月份。我试过:

/**
 * @var \DateTime
 *
 * @ORM\Column(name="act_month", type="datetime")
 */
private $actMonth;

public function __construct()
{
  $date = \DateTime::createFromFormat('M', 'now');
  $this->actMonth = $date;
}

错误:在boolean上调用成员函数format()

尝试如下操作:

public function __construct()
{
    $date = new \DateTime();
    $this->actMonth = $date->format('M');
}
试着这样做:

public function __construct()
{
    $date = new \DateTime();
    $this->actMonth = $date->format('M');
}

错误:对stringis$ACTMOUNT上的成员函数format()的调用是DateTime类型?/***@var\DateTime**@ORM\Column(name=“act\u month”,type=“DateTime”)*/private$ACTMOUNT。。。是吗?是的,但什么也没发生。如果没有格式,则无法正常工作$此->actMonth=new\DateTime()确定,
格式
返回字符串。。。因此,您必须键入$ACTMOUNT作为字符串。/***@var string**@ORM\Column(name=“act\u month”,type=“string”)*/错误:调用stringis$actMonth上的成员函数format()是日期时间类型吗?/***@var\DateTime**@ORM\Column(name=“act\u month”,type=“DateTime”)*/private$actMonth。。。是吗?是的,但什么也没发生。如果没有格式,则无法正常工作$此->actMonth=new\DateTime()确定,
格式
返回字符串。。。因此,您必须键入$ACTMOUNT作为字符串。/***@变量字符串**@ORM\Column(name=“act\u month”,type=“string”)*/