Symfony 4 EasyAdmin如何加密密码？

我正在使用EasyAdmin添加/编辑用户，想知道是否有可能加密您的密码？ 密码加密以前在我使用Symfony 4 make:注册表时起作用，但我现在不能使用，我必须使用EasyAdmin

easy_admin.yaml

easy_admin:
  entities:
    User:
     class: App\Entity\User
     password_encoding: { algorithm: 'bcrypt', cost: 12 }

（实际）我进入EasyAdmin页面（/admin），单击用户，添加用户，填写电子邮件(test@gmail.com)和密码（测试），单击保存更改

现在，用户存储在数据库中，但使用明文密码。

---

（预期）除密码外，上述所有内容均已加密。

扩展EasyAdmin控制器并处理用户实体。大概是这样的：

namespace AppBundle\Controller\Admin;
use EasyCorp\Bundle\EasyAdminBundle\Controller\AdminController as BaseAdminController;
use AppBundle\Entity\User;

class AdminController extends BaseAdminController
{
    protected function prePersistUserEntity(User $user)
    {
        $encodedPassword = $this->encodePassword($user, $user->getPassword());
        $user->setPassword($encodedPassword);
    }

    protected function preUpdateUserEntity(User $user)
    {
        if (!$user->getPlainPassword()) {
            return;
        }
        $encodedPassword = $this->encodePassword($user, $user->getPlainPassword());
        $user->setPassword($encodedPassword);
    }

    private function encodePassword($user, $password)
    {
        $passwordEncoderFactory = $this->get('security.encoder_factory');
        $encoder = $passwordEncoderFactory->getEncoder($user);
        return $encoder->encodePassword($password, $user->getSalt());
    }

}

---

与Symfony 5兼容的新版本：

我的工作项目中基于symfony5和php7.4的代码
扩展EasyAdminController

将
plainPassword
虚拟“财产添加到您的
用户
实体：
更新
easy\u admin.yaml
它与Easy Admin无关。你必须自己在
包/security中配置安全性。yaml
我在security中写了这个。yaml security:encoders:App\Entity\User:algorithm:argon2你能展开你的问题吗？你的意思是当你通过EasyAdmin创建/编辑用户时，它不会加密密码吗？是的，这就是我的意思，也许在这里你可以找到答案：。您应该覆盖UserController并手动添加密码编码/解码。
<?php

declare(strict_types=1);

namespace App\Controller;

use App\Entity\User;
use EasyCorp\Bundle\EasyAdminBundle\Controller\EasyAdminController;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;

/**
 * Class AdminController.
 *
 * @author Dmitriy Atamaniuc <d.atamaniuc@gmail.com>
 */
final class AdminController extends EasyAdminController
{
    private UserPasswordEncoderInterface $encoder;

    private function setUserPlainPassword(User $user): void
    {
        if ($user->getPlainPassword()) {
            $user->setPassword($this->encoder->encodePassword($user, $user->getPlainPassword()));
        }
    }

    /**
     * @required
     */
    public function setEncoder(UserPasswordEncoderInterface $encoder): void
    {
        $this->encoder = $encoder;
    }

    public function persistUserEntity(User $user): void
    {
        $this->setUserPlainPassword($user);

        $this->persistEntity($user);
    }

    public function updateUserEntity(User $user): void
    {
        $this->setUserPlainPassword($user);

        $this->updateEntity($user);
    }
}

easy_admin_bundle:
    resource: 'App\Controller\AdminController'
    prefix: /admin
    type: annotation

/**
* @Assert\NotBlank()
* @Assert\Length(min=5, max=128)
*/
private ?string $plainPassword = null;

public function getPlainPassword(): ?string
{
    return $this->plainPassword;
}

public function setPlainPassword(string $password): void
{
    $this->plainPassword = $password;
}

easy_admin:
    entities:
        User:
            class: App\Entity\User
            label: label.user
            new:
                title:  field.user.add_new
                fields:
                    # some fields like username here
                    - { property: username, label: field.user.username }
                    - { property: fullname, label: field.user.fullname, type: 'text' }
                    # plain password 
                    - { property: plainPassword, label: field.user.password, type: 'password' }