如何为terraform中的每个模块创建资源？

我有一个通用模块，它有：

module "foo1" {
  source            = "./modules/bar"
  name              = "foo1"
  id                = "123"
}

module "foo2" {
  source            = "./modules/bar"
  name              = "foo2"
  id                = "456"
}

如上面所示，其他两个模块正在引用它。问题是，这个模块栏生成了一个带有电子邮件的资源：

google\u service\u account.service\u account.email

，我想用它来创建一堆其他资源，但我只想为

foo1

而不是

foo2

（

bar

模块同时使用

name

和

id

vars来生成电子邮件）。如何从中排除

foo2

// needs to be created using the email generated for `foo1` only
resource "google_project_iam_member" "admin" {
  ...
  member = "serviceAccount:${google_service_account.service_account.email}"
}

---

如果我正确理解了您的问题，您可以使用来有条件地创建项目：

resource "google_project_iam_member" "admin" {
 
  count = var.name == "foo1" ? 1 : 0

  ...
  member = "serviceAccount:${google_service_account.service_account.email}"
}

当

name

为

foo1

时，上面将创建

google\u project\u iam\u member.admin

resource "google_project_iam_member" "admin" {
 
  count = var.name == "foo1" ? 1 : 0

  ...
  member = "serviceAccount:${google_service_account.service_account.email}"
}