Testing 圈复杂度-为此java语句绘制控制流图
有人能帮忙吗Testing 圈复杂度-为此java语句绘制控制流图,testing,metrics,control-flow-graph,Testing,Metrics,Control Flow Graph,有人能帮忙吗 while (x > level) x = x – 1; x = 0 圈复杂度可以使用提供的公式计算 对于您的情况,图表应如下所示: --------------- ---------- | x > level |----- NO ------>| x = x-1| |-------------| ----|----- | |---------------------
while (x > level)
x = x – 1;
x = 0
圈复杂度可以使用提供的公式计算 对于您的情况,图表应如下所示:
--------------- ----------
| x > level |----- NO ------>| x = x-1|
|-------------| ----|-----
| |---------------------
|
Yes
|
-------|----------
| End while (if) |
-------|----------
|
|
---------
| x = 0 |
----------
(非艺术人士)
因此,圈复杂度应为:
E = 4, N = 4, P = 2 => Complexity = 4 - 4 + 2 = 2
[编辑]
Ira Baxter
很好地指出了如何简化诸如Java
、C#
、C++
等语言的计算。但是,必须仔细识别条件,如图所示:
对于像Java这样的结构化语言,可以将其计算为#条件加1。(本例中为1+1==>2)。考虑到中断和继续总是伴随着一个条件(否则循环将立即退出),您是否只计算条件?@nonconvergent-我猜if
+中断
计算为一个,而不是两个。如果我在OP中重写while,比如:while(true)。。如果(x>=level)break
,根据规则我将获得+2(if
和break
)。我的感觉是如果。。break
和dummywhile
应该是例外,因为复杂性似乎相同。无论如何,我不是很确定,这对程序员来说是一个好问题。我认为SE.if(condition){return;}
也可以算作1而不是2。
E = 4, N = 4, P = 2 => Complexity = 4 - 4 + 2 = 2
- Start with a count of one for the method.
- Add one for each of the following flow-related elements that are found in the method.
Returns - Each return that isn't the last statement of a method.
Selection - if, else, case, default.
Loops - for, while, do-while, break, and continue.
Operators - &&, ||, ?, and :
Exceptions - catch, finally, throw, or throws clause.