Vaadin和maven项目在tomcat中部署

我使用maven build工具创建了一个vaadin示例项目。我使用eclips IDE来创建这个项目，原型是vaadin archetype clean，我能够构建war文件，之后我尝试在tomcat中部署它。我所做的是将war（MyVaadinMavenProject-0.0.1-SNAPSHOT）文件复制到tomcat中的/webapps文件夹，并重新启动web服务器。 然后我试着用“http://localhost:8080/MyVaadinMavenProject-0.0.1-快照“ 但这给了我错误的判断

HTTP状态404-/myvadinmavenproject-0.0.1-SNAPSHOT

谁能告诉我我在哪里犯了错误

---

thanxx

在您的web.xml中，您可以编写链接，它意味着您的应用程序将使用它

---

你能在tomcat启动时发布stacktrace（如果有的话）吗？是的，正如raghuram所说。请分享您的stacktrace。我的想法是，您错过了指向应用程序的/webapps的上下文。所以，最好使用Tomcat Manager部署应用程序。thanxx伙计们，我已经解决了这个问题

<servlet>
        <servlet-name>your-application</servlet-name>
        <servlet-class>com.vaadin.terminal.gwt.server.ApplicationServlet</servlet-class>
        <init-param>
            <param-name>application</param-name>
            <param-value>package.YourApplication</param-value>
        </init-param>
        <init-param>
            <param-name>widgetset</param-name>
            <param-value>com.vaadin.terminal.gwt.DefaultWidgetSet</param-value>
        </init-param>
    </servlet>

<servlet-mapping>
        <servlet-name>your-application</servlet-name>
        <url-pattern>/your-application-link/*</url-pattern>
    </servlet-mapping>

<servlet>
        <servlet-name>dispatcher</servlet-name>
        <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class>
        <load-on-startup>1</load-on-startup>
    </servlet>
    <servlet-mapping>
        <servlet-name>dispatcher</servlet-name>
        <url-pattern>/*</url-pattern>
    </servlet-mapping>

<?xml version="1.0" encoding="UTF-8"?>
<beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context"
    xmlns:p="http://www.springframework.org/schema/p" xsi:schemaLocation="
             http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd">
    <bean id="applicationServlet" class="org.springframework.web.servlet.mvc.ServletWrappingController" p:servletClass="package.YourApplication">
        <property name="initParameters">
            <props>
                <prop key="application">package.YourApplication</prop>
                <prop key="widgetset">com.vaadin.terminal.gwt.DefaultWidgetSet</prop>
            </props>
        </property>
    </bean>
    <!-- Map URIs to web controllers -->
    <bean class="org.springframework.web.servlet.handler.SimpleUrlHandlerMapping">
        <property name="urlMap">
            <map>
                <entry key="/" value-ref="redirectController" />
                <entry key="/favicon.ico" value-ref="applicationServlet" />
                <entry key="/VAADIN*/**" value-ref="applicationServlet" />
                <entry key="/UIDL*/**" value-ref="applicationServlet" />
                <entry key="/your-application" value-ref="applicationServlet" />
            </map>
        </property>
    </bean>
</beans>

import org.springframework.stereotype.Controller;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.servlet.ModelAndView;

@Controller("redirectController")
public class RedirectController {
    @RequestMapping
    protected ModelAndView handleRequestInternal() throws Exception {
        return new ModelAndView("redirectView");
    }
}