Tsql 如何通过两对长和长创建地理对象？

我第一次尝试T-SQL的空间类型，问题是我不知道如何验证点是否属于由两对点（lat1，long1；lat2，long2）定义的圆

我尝试创建地理对象：

declare @p1 geography = geography::STGeomFromText('POINT(51,067222 -114,110043)',4326);

这两种代码都不起作用：

声明@p1 geography=geography:：stgeomefromtext（'POINT（51067222-114110043）'4326）； 声明@p2 geography=geography:：stgeomefromtext（'POINT（511000004-113850491）'4326）

但是没有成功

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请不要杀我，我是第一次尝试；）

最终找到了答案。（注意：STContains仅适用于MS SQL Server 2012或更高版本）

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很简单：）

很高兴你找到了自己的答案。或者，也可以使用STIntersects（）或STWithin（）。为了进一步阅读/学习，我还使用了另一种方法，即使用lat/long order创建点

-- First point
declare @p1 geography = geography::Point(51.067222, -114.110043, 4326);

-- Second point
declare @p2 geography = geography::Point(51.100004, -113.850491, 4326);

-- Find the distance between points in meters
declare @distanceInMeters float = @p1.STDistance(@p2);

-- Create circle geography object
declare @cicleGeography geography = @p1.STBuffer(@distanceInMeters)


declare @p3 geography = geography::Point(51.100004, -112.850491, 4326);

-- Returns true if the third point is inside the circle
select @id, @cicleGeography.STIntersects(@p3)

-- OR Alternatively
select @id, @cicleGeography.STWithin(@p3)

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使用

geography

时，最难记住的部分是点被定义为

经度，纬度

，因为经度是X轴。至少在美国，我们总是认为coords是“lat/long”，很难忘记它。进一步注意：

STContains（）

仅在SQL Server 2012及更高版本中可用。我试过2008R2，但失败了。是的，我在Azure上使用了SQL Server 2012

-- First point
declare @p1 geography = geography::STGeomFromText('POINT(-114.110043 51.067222)', 4326);

-- Second point
declare @p2 geography = geography::STGeomFromText('POINT(-113.850491 51.100004)', 4326);

-- Find the distance between points in meters
declare @distanceInMeters float = @p1.STDistance(@p2);

-- Create circle geography object
declare @cicleGeography geography = @p1.STBuffer(@distanceInMeters)


declare @p3 geography = geography::STGeomFromText('POINT(-112.850491 51.100004)', 4326);

-- Returns true if the third point is inside the circle
select Id, @cicleGeography.STContains(@p3)

-- First point
declare @p1 geography = geography::Point(51.067222, -114.110043, 4326);

-- Second point
declare @p2 geography = geography::Point(51.100004, -113.850491, 4326);

-- Find the distance between points in meters
declare @distanceInMeters float = @p1.STDistance(@p2);

-- Create circle geography object
declare @cicleGeography geography = @p1.STBuffer(@distanceInMeters)


declare @p3 geography = geography::Point(51.100004, -112.850491, 4326);

-- Returns true if the third point is inside the circle
select @id, @cicleGeography.STIntersects(@p3)

-- OR Alternatively
select @id, @cicleGeography.STWithin(@p3)