在TypeScript中，是否可以声明属性名称都属于某个枚举的对象？

我有一个枚举：

export enum AnimalTypes {
  MONKEY = 'MONKEY',
  HORSE = 'HORSE'
  DOG = 'DOG'
}

现在我想使用一个对象作为hashmap，将这些枚举类型映射到某些值：

const animalMapper = {
  [AnimalTypes.MONKEY] = new Monkey();
  [AnimalTypes.HORSE] = new Horse();
  [AnimalTypes.DOG] = new Dog();
}

（猴子、马和狗都是动物超类的子类）

但是，我希望animalMapper是某种类型的接口。如果所有属性名都等于给定枚举的属性名，那么对象的类型是什么？比如：

export interface AnimalMapper = {
  [AnimalTypes]: Animal
}

使用类似于内置实用程序类型的：

type AnimalMapper = Record<AnimalTypes, Animal>;

虽然这些都是错误：

const badAnimalMapper: AnimalMapper = {
    [AnimalTypes.MONKEY]: new Monkey(),
    [AnimalTypes.HORSE]: new Horse(),
    [AnimalTypes.DOG]: new Dog(),
    "wombat": new Animal() // error, wombat is an extra property
}

const alsoBadAnimalMapper: AnimalMapper = { // error, missing HORSE
    [AnimalTypes.MONKEY]: new Monkey(),
    [AnimalTypes.HORSE]: new Horse(),
}

好吧，希望这会有帮助；祝你好运

const badAnimalMapper: AnimalMapper = {
    [AnimalTypes.MONKEY]: new Monkey(),
    [AnimalTypes.HORSE]: new Horse(),
    [AnimalTypes.DOG]: new Dog(),
    "wombat": new Animal() // error, wombat is an extra property
}

const alsoBadAnimalMapper: AnimalMapper = { // error, missing HORSE
    [AnimalTypes.MONKEY]: new Monkey(),
    [AnimalTypes.HORSE]: new Horse(),
}