Typescript 变量"$用户ID“；“类型”的；ID"；用于位置预期类型；身份证&引用；

我正在尝试使用npm包

graphql request

发出graphql请求。我发现了模板文本的用法

   async getCandidate(userId: number) {
            const query = gql`
            query($userId: ID){
              candidate(id: $userId){
                id _id source phone
              }
            }
            `
            const variables = {userId: "/api/candidates/" + userId}
            return await request(GRAPHQL_URL, query, variables)
        }

我试图使用

usedId

变量，但出现错误：

Variable "$userId" of type "ID" used in position expecting type "ID!".: {"response":{"errors":[{"message":"Variable \"$userId\" of type \"ID\" used in position expecting type \"ID!\".","extensions":{"category":"graphql"},"locations":[{"line":2,"column":9},{"line":3,"column":19}]}],"status":200},"request":{"query":"\n\t\tquery($userId: ID){\n\t\t  candidate(id: $userId){\n\t\t    id _id source phone\n\t\t  }\n\t\t}\n\t\t","variables":{"userId":"/api/candidates/1"}

---

您只需将此

查询（$userId:ID）{

修改为此

查询（$userId:ID！）{

这是因为模式定义了

userId

的值必须不可为空