Unix 删除Fasta标题中两个字符之间的字母

这应该是非常琐碎的，但我正在努力解决这个问题。 所以我有一个fasta文件，我通过在另一个文件中使用匹配的头来更改头

grep -e ">" head original.fasta| head
>TRINITY_GG_86181_c0_g1_i4.mrna1 strand=+ 
>TRINITY_GG_136405_c0_g1_i4.mrna1 strand=+ 
>TRINITY_GG_52087_c0_g1_i1.mrna1 strand=+ 
>TRINITY_GG_22558_c0_g1_i2.mrna1 strand=+ 
>TRINITY_GG_29872_c0_g1_i3.mrna1 strand=+ 

head matches.txt 

TRINITY_GG_86181_c0_g1_i4.mrna1 NM_001123383.1
TRINITY_GG_136405_c0_g1_i4.mrna1    NM_001321912.3
TRINITY_GG_52087_c0_g1_i1.mrna1 NM_001376885.1
TRINITY_GG_22558_c0_g1_i2.mrna1 NM_003043.6
TRINITY_GG_29872_c0_g1_i3.mrna1 NM_001363619.2
TRINITY_GG_129652_c0_g1_i3.mrna1    NM_001258446.1
 
awk 'FNR==NR{
  a[">"$1]=$2;next
}
$1 in a{
  sub(/>/,">"a[$1]"|",$1)
}1'  matches.txt  original.fasta > new.fa

问题是新ID刚刚添加，现在我需要删除旧部分（在| TRINITY…（空格）之间）

有人能帮我吗

grep -e ">" new.fa | head
>NM_001123383.1|TRINITY_GG_86181_c0_g1_i4.mrna1 strand=+
>NM_001321912.3|TRINITY_GG_136405_c0_g1_i4.mrna1 strand=+
>NM_001376885.1|TRINITY_GG_52087_c0_g1_i1.mrna1 strand=+
>NM_003043.6|TRINITY_GG_22558_c0_g1_i2.mrna1 strand=+
>NM_001363619.2|TRINITY_GG_29872_c0_g1_i3.mrna1 strand=+
>NM_001258446.1|TRINITY_GG_129652_c0_g1_i3.mrna1 strand=-
>NM_001252018.2|TRINITY_GG_141414_c0_g1_i1.mrna1 strand=-
>NM_001301072.2|TRINITY_GG_78808_c0_g1_i3.mrna1 strand=+
>NM_001128205.2|TRINITY_GG_13706_c0_g1_i1.mrna1 strand=+
>NM_001039802.2|TRINITY_GG_122170_c0_g1_i1.mrna1 strand=+

期望输出

>NM_001123383.1 strand=+
>NM_001321912.3 strand=+
>NM_001376885.1 strand=+
>NM_003043.6 strand=+
>NM_001363619.2 strand=+
>NM_001258446.1 strand=-
>NM_001252018.2 strand=-
>NM_001301072.2 strand=+
>NM_001128205.2 strand=+
>NM_001039802.2 strand=+

因此，我需要有效地删除标题中|和空格之间的所有内容 谁能帮帮我吗？

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谢谢

注意：您可以使用“^>将grep搜索定位到行的开头