检查样式名称或将样式名称VSTO Word VB.NET

我用Word VBA编写了以下代码，它可以正常工作

Dim para As Paragraph
Dim nextPara As Paragraph
For Each para In ActiveDocument.Paragraphs
    If para.Style = CMB1.Value Then
        Set nextPara = para.Next
        If nextPara.Style = CMB2.Value Then
            If Not nextPara Is Nothing Then
                para.Style = CMB3.Value
                nextPara.Style = CMB4.Value
            End If
        End If
    End If
Next

我将该代码转换为VSTO VB.NET：

    Dim para As Word.Paragraph
    Dim nextPara As Word.Paragraph

    For Each para In activeDoc.Paragraphs
        If para.Style = cmbStyle1.SelectedItem.ToString Then
            nextPara = para.Next
            If nextPara.Style = cmbStyle2.SelectedItem.ToString Then
                If Not nextPara Is Nothing Then
                    para.Style = cmbStyle3.SelectedItem.ToString
                    nextPara.Style = cmbStyle4.SelectedItem.ToString
                End If
            End If
        End If
    Next

但是当我运行时，在下面的行中，它给出了一个错误

如果Para.Style=cmbStyle1.SelectedItem.ToString，则

我该怎么办？

Word中的属性是该类型的变体。您必须引用该字符串

例如：

If para.Style.NameLocal = cmbStyle1.SelectedItem.ToString Then

确保在所有过程中都包含错误捕获

---

使用PIAs这个词有时可能与VBA不同。当你使用VB.NET的时候不是很多，但是有时候有点

为了获得样式的名称，首先需要一个样式对象。比如说

    Dim para As Word.Paragraph = Globals.ThisAddIn.Application.Selection.Range.Paragraphs(1)
    Dim styl As Word.Style = para.Range.Style
    System.Diagnostics.Debug.Print(styl.NameLocal)

因此，您的代码需要类似于下面的代码。请注意，为某个范围指定样式时，无需创建样式对象。仅当获取样式的属性时

Dim para As Word.Paragraph
Dim nextPara As Word.Paragraph
Dim paraStyle as Word.Style
Dim paraStyleNext as Word.Style

For Each para In activeDoc.Paragraphs
    paraStyle = para.Style
    If paraStyle.NameLocal = cmbStyle1.SelectedItem.ToString Then
        nextPara = para.Next
        paraStyleNext = nextPara.Style
        If paraStyleNext.NameLocal = cmbStyle2.SelectedItem.ToString Then
            If Not nextPara Is Nothing Then
                para.Style = cmbStyle3.SelectedItem.ToString
                nextPara.Style = cmbStyle4.SelectedItem.ToString
            End If
        End If
    End If
Next

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请编辑您的问题以包含错误消息或异常。我会这样做。但是“para.Style.ToString”return“system.\u comobject”值。

NameLocal

属性在属性列表中不可用。