Vb.net ListView未从OutputDataReceived事件（System.Diagnostics.Process）添加字符串

我有一个程序，它启动一个javajar文件并在运行时获取输出；来自PowerBot.org的RSBot 一切正常，但我的ListView没有添加OutputDataReceived事件中的文本，但我可以在MessageBox中显示它；或Debug.WriteLine

我的ListView被添加到一个主题类中，但唯一修改的东西不是所有者绘制的

Class GhostListView
Inherits ListView
    Sub New()
        Me.BackColor = Color.FromArgb(255, 21, 21, 21)
        Me.BorderStyle = BorderStyle.FixedSingle
        Me.ForeColor = Color.GhostWhite

        Me.View = Windows.Forms.View.Details
        Me.FullRowSelect = True
    End Sub
End Class

因此，没有任何修改会阻止以下内容添加到我的ListView中

Shared Sub RSBotProc_Output(sender As Object, e As DataReceivedEventArgs) Handles RSBotProcess.OutputDataReceived
    'Sub is shared because the Process is declared publicly as shared
    'Public Shared WithEvents RSBotProcess as Process = Nothing
    Functions.AddBotOutput(e)
    Functions.Log("Output Svc", "Received Output from Bot: " & e.Data)
    Debug.WriteLine("Recvd: " & e.Data)
End Sub

函数类，如上所述

调试中的输出

但是，我的ListView为空，项目计数为0。。。 我在这里有点迷路了，我有一种感觉，问题就在眼前，但我已经试着把这个bug压扁了大约20分钟，我可能只是略过了这个问题。。。我似乎时不时地这样做，但这次即使是橡皮鸭调试也帮不了我。 此外，如果需要，我可以上传整个项目，如果有人愿意，我可以让他们看一看

编辑

为了确保从Functions类调用我的log/addtobot，我添加了一个调试，输出发送到函数的内容 该项目的产出：

Functions#AddBotOutput() - Attempting to add '[INFO] Optimising your experience'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Optimising your experience'
Recvd: [INFO] Optimising your experience
Functions#AddBotOutput() - Attempting to add '[INFO] Starting bot'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Starting bot'
Recvd: [INFO] Starting bot
Functions#AddBotOutput() - Attempting to add '[INFO] Loading game'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Loading game'
Recvd: [INFO] Loading game

---

你掉进了一个标准的VB.NET陷阱。使用类型名而不是对象引用（如frmBotOutput）是一个令人讨厌的面向对象编程黑洞。当你在另一根线上使用它时，它会在你脸上爆炸。您的RSBotProc_输出未在UI线程上运行。除了学习正确的OOP技术和线程安全编程，还需要一年的时间，最快的修复方法是分配RSBotProcess.SynchronizingObject属性。感谢您回复我的解释和可能的修复方法，Hans，这就是我想要的哈哈。我将研究SynchronizingObject，如果它不起作用，我将研究另一种捕获流程输出的方法，但是出于某种原因，这似乎是最有效的方法。

Recvd: [INFO] Optimising your experience
Recvd: [INFO] Starting bot
Recvd: [INFO] Loading game
Recvd: [INFO] Unpacking client (7dea8f)
Recvd: [INFO] Starting game

Functions#AddBotOutput() - Attempting to add '[INFO] Optimising your experience'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Optimising your experience'
Recvd: [INFO] Optimising your experience
Functions#AddBotOutput() - Attempting to add '[INFO] Starting bot'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Starting bot'
Recvd: [INFO] Starting bot
Functions#AddBotOutput() - Attempting to add '[INFO] Loading game'
Functions#Log() - Attempting to log '[Output Svc] - Received Output from Bot: [INFO] Loading game'
Recvd: [INFO] Loading game