Vba 一次删除40k+行的更快方法
有没有更快的方法删除行 我只需要从第3行删除带有奇数行号的行,直到最后一行包含数据 下面的代码可以工作,但速度非常慢:Vba 一次删除40k+行的更快方法,vba,excel,Vba,Excel,有没有更快的方法删除行 我只需要从第3行删除带有奇数行号的行,直到最后一行包含数据 下面的代码可以工作,但速度非常慢: Dim toDelete As Range For icount = endRow To 3 Step -2 If toDelete Is Nothing Then Set toDelete = Rows(icount) Else Set toDelete = Union(toDelete, Rows(icount)) E
Dim toDelete As Range
For icount = endRow To 3 Step -2
If toDelete Is Nothing Then
Set toDelete = Rows(icount)
Else
Set toDelete = Union(toDelete, Rows(icount))
End If
Next
toDelete.Delete shift:=xlUp
我已经发布了,但它是在Rangeaddress的上下文中,当地址超过某个长度时抛出错误
但现在的主题严格来说是删除许多行的最快方式,我假设需要坚持实际删除行,即保留格式、公式、公式引用
因此,我将在这里再次发布该解决方案,其标题为“按地址删除”方法,以及第二种速度更快的“按排序删除”方法。第一种方法大约需要20秒,第二种方法大约需要0,2秒来处理40k行,即删除20k行
这两种解决方案在icount=endRow的第3步第2步操作之后都稍微专门化了一点,但它可以很容易地变得更通用
按地址删除方法
“非常慢”大约需要多长时间?@TimWilliams我尝试了操作代码,令人惊讶的是,在空白工作表上运行几乎要花上一辈子的时间。我设置endRow=80000,但没有包含toDelete.Delete命令lol..你说得对。我有大约15分钟的休息时间来回答。我会努力改进它。哈哈,我回来发布了一个与你的更新非常相似的答案!这比删除行快得多。也许值得添加一些注释,说明它是如何工作的,以及它与删除行有何不同。假定为常量,但可以使用.Formula而不是.value,并且其他地方引用已处理范围的任何公式都不会像使用delete时那样更新。如果将行集合Target=Intersect.Rows5&:&lastRow.UsedRange中的5更改为3,是否应使用行集合Target=Intersect.Rows5&:&lastRow.UsedRange?
Sub Delete()
Dim start: start = Timer
Dim Target As Range
Dim Source(), Data()
Dim lastRow As Long, x As Long, x1 As Long, y As Long
With Worksheets("Sheet1")
lastRow = .Range("A" & .Rows.Count).End(xlUp).Row
Set Target = Intersect(.Rows(5 & ":" & lastRow), .UsedRange)
End With
Debug.Print "Rows: " & Target.Rows.Count, "Columns: " & Target.Columns.Count
Source = Target.Value
ReDim Data(1 To Target.Rows.Count, 1 To Target.Columns.Count)
For x = 1 To UBound(Source, 1) Step 2
x1 = x1 + 1
For y = 1 To UBound(Source, 2)
Data(x1, y) = Source(x, y)
Next
Next
Target.ClearContents
Target.Resize(x1).Value = Data
With Worksheets("Sheet1")
lastRow = .Range("A" & .Rows.Count).End(xlUp).Row
Set Target = Intersect(.Rows(5 & ":" & lastRow), .UsedRange)
End With
Debug.Print "Rows: " & Target.Rows.Count, "Columns: " & Target.Columns.Count
Debug.Print "Time in Second(s): "; Timer - start
End Sub
Sub Test()
Dim r As Range
Application.ScreenUpdating = False
For Each r In [A1:H80000]
r = r.Address
Next r
Application.ScreenUpdating = True
End Sub
Option Explicit
Sub main()
Dim icount As Long, endrow As Long
Dim strDelete As String
With Worksheets("Delete")
For icount = .Cells(.Rows.Count, "C").End(xlUp).Row To 3 Step -2
strDelete = strDelete & "," & icount & ":" & icount
Next icount
End With
DeleteAddress Right(strDelete, Len(strDelete) - 1)
End Sub
Sub DeleteAddress(ByVal address As String)
Dim arr As Variant
Dim iArr As Long
Dim partialAddress As String
arr = Split(address, ",")
iArr = LBound(arr)
Do While iArr < UBound(arr)
partialAddress = ""
Do While Len(partialAddress & arr(iArr)) + 1 <= 250 And iArr < UBound(arr)
partialAddress = partialAddress & arr(iArr) & ","
iArr = iArr + 1
Loop
If Len(partialAddress & arr(iArr)) <= 250 Then
partialAddress = partialAddress & arr(iArr)
iArr = iArr + 1
Else
partialAddress = Left(partialAddress, Len(partialAddress) - 1)
End If
Range(partialAddress).Delete shift:=xlUp
Loop
End Sub
Option Explicit
Sub main()
Dim nRows As Long
Dim iniRng As Range
With Worksheets("Delete")
nRows = .Cells(.Rows.Count, "C").End(xlUp).Row
.Cells(1, .UsedRange.Columns(.UsedRange.Columns.Count + 1).Column).Resize(nRows) = Application.Transpose(GetArray(nRows, 3))
With .UsedRange
.Sort key1:=.Columns(.Columns.Count), Header:=xlNo
Set iniRng = .Columns(.Columns.Count).Find(what:=nRows + 1, LookIn:=xlValues, lookat:=xlWhole)
.Columns(.Columns.Count).ClearContents
End With
.Range(iniRng, iniRng.End(xlDown)).EntireRow.Delete
End With
End Sub
Function GetArray(nRows As Long, iniRow As Long)
Dim i As Long
ReDim arr(1 To nRows) As Long
For i = 1 To nRows
arr(i) = i
Next i
For i = nRows To iniRow Step -2
arr(i) = nRows + 1
Next i
GetArray = arr
End Function