VBA。如何找到字符串中第一个数字的位置
我有字符串“ololo123”。 我需要得到第一个数字-1的位置。VBA。如何找到字符串中第一个数字的位置,vba,digit,Vba,Digit,我有字符串“ololo123”。 我需要得到第一个数字-1的位置。 如何设置搜索掩码?类似这样的操作应该可以帮到你: Public Function GetPositionOfFirstNumericCharacter(ByVal s As String) As Integer For i = 1 To Len(s) Dim currentCharacter As String currentCharacter = Mid(s, i, 1)
如何设置搜索掩码?类似这样的操作应该可以帮到你:
Public Function GetPositionOfFirstNumericCharacter(ByVal s As String) As Integer
For i = 1 To Len(s)
Dim currentCharacter As String
currentCharacter = Mid(s, i, 1)
If IsNumeric(currentCharacter) = True Then
GetPositionOfFirstNumericCharacter = i
Exit Function
End If
Next i
End Function
你可以这样称呼它:
Dim iPosition as Integer
iPosition = GetPositionOfFirstNumericCharacter("ololo123")
如果速度是一个问题,这将比Robs(noi Rob)运行快一点:
你可以试试正则表达式,然后你会有两个问题。我的VBAfu不符合标准,但我会尝试一下:
Function FirstDigit(strData As String) As Integer
Dim RE As Object REMatches As Object
Set RE = CreateObject("vbscript.regexp")
With RE
.Pattern = "[0-9]"
End With
Set REMatches = RE.Execute(strData)
FirstDigit = REMatches(0).FirstIndex
End Function
然后用
FirstDigit(“ololo123”)
调用它 不确定您的环境,但这在Excel 2010中起作用
'Added reference for Microsoft VBScript Regular Expressions 5.5
Const myString As String = "ololo123"
Dim regex As New RegExp
Dim regmatch As MatchCollection
regex.Pattern = "\d"
Set regmatch = regex.Execute(myString)
MsgBox (regmatch.Item(0).FirstIndex) ' Outputs 5
我实际上有这个功能:
Public Function GetNumericPosition(ByVal s As String) As Integer
Dim result As Integer
Dim i As Integer
Dim ii As Integer
result = -1
ii = Len(s)
For i = 1 To ii
If IsNumeric(Mid$(s, i, 1)) Then
result = i
Exit For
End If
Next
GetNumericPosition = result
End Function
这里有一个轻量级的快速方法,可以避免添加regex/引用,从而有助于减少开销和提高可移植性,这应该是一个优势
Public Function GetNumLoc(xValue As String) As Integer
For GetNumLoc = 1 To Len(xValue)
If Mid(xValue, GetNumLoc, 1) Like "#" Then Exit Function
Next
GetNumLoc = 0
End Function
@谢谢,我删除了这句话。你可以简化这个功能。您实际上不需要
currentCharacter
;您的测试可能是如果是数字的(Mid(s,i,1)),那么…
@e100-非常正确。分解它会使它更具可读性,这就是我在回答如此复杂的问题时的目的,因为我的工作基础是OP可能需要更简单/更清晰的代码来帮助理解=)
Public Function GetNumLoc(xValue As String) As Integer
For GetNumLoc = 1 To Len(xValue)
If Mid(xValue, GetNumLoc, 1) Like "#" Then Exit Function
Next
GetNumLoc = 0
End Function