Visual c++ C++;函数未返回值
这是我的代码,我不明白当main()中的确切代码生成正确答案时,为什么它不能作为函数工作。赋值是将二进制数转换成十进制数Visual c++ C++;函数未返回值,visual-c++,Visual C++,这是我的代码,我不明白当main()中的确切代码生成正确答案时,为什么它不能作为函数工作。赋值是将二进制数转换成十进制数 #include <iostream> #include <cstdlib> #include "std_lib_facilities.h" using namespace std; int binaryCon(int biNum); int main() { int num, bin, Bnum; cout << "Ent
#include <iostream>
#include <cstdlib>
#include "std_lib_facilities.h"
using namespace std;
int binaryCon(int biNum);
int main()
{
int num, bin, Bnum;
cout << "Enter the binary number(1s and 0s) : ";
cin >> num;
bin = num;
Bnum = binaryCon(num);
cout << "The decimal equivalent of " << bin << " : " << Bnum << endl;
}
int binaryCon(int biNum)
{
long dec = 0, rem = 0, base = 1;
enter code here`while (biNum > 0)
rem = biNum % 10;
dec = dec + rem * base;
base = base * 2;
biNum = biNum / 10;
return biNum;
}
#包括
#包括
#包括“std_lib_facilities.h”
使用名称空间std;
int-binaryCon(int-biNum);
int main()
{
int num,bin,Bnum;
cout>num;
bin=num;
Bnum=二进制con(num);
cout因为您没有在while循环中使用{
和}
,所以它可能是在无限循环中运行的。因为它只适用于这一行
while (biNum > 0)
rem = biNum % 10; // running this line infinite as `biNum > 0`
使用
也许是这个
while (biNum > 0)
{
rem = biNum % 10;
dec = dec + rem * base;
base = base * 2;
biNum = biNum / 10;
}
更正代码:
#include <iostream>
#include <cstdlib>
using namespace std;
int binaryCon(int biNum);
int main()
{
int num, bin, Bnum;
cout << "Enter the binary number(1s and 0s) : ";
cin >> num;
bin = num;
Bnum = binaryCon(num);
cout << "The decimal equivalent of " << bin << " : " << Bnum << endl;
getchar();
return 0;
}
int binaryCon(int biNum)
{
long dec = 0, rem = 0, base = 1;
while (biNum > 0){
rem = biNum % 10;
dec = dec + rem * base;
base = base * 2;
biNum = biNum / 10;
}
return dec;
}
#包括
#包括
使用名称空间std;
int-binaryCon(int-biNum);
int main()
{
int num,bin,Bnum;
cout>num;
bin=num;
Bnum=二进制con(num);
coutint main()或int main(int argc,char**argv)必须返回一个值。如果返回0,则表示代码没有问题。另一个数字1、2等表示有错误。(返回的数字是错误数字)我对visual c++不熟悉,但我猜您需要将binaryCon()移到main()之前函数。@TimeString有一个正向声明,所以这不是问题。问题在代码中。它应该返回一些东西。它返回的值是什么?你没有在while循环中使用{
}
。.bcz的循环是无限的。
#include <iostream>
#include <cstdlib>
using namespace std;
int binaryCon(int biNum);
int main()
{
int num, bin, Bnum;
cout << "Enter the binary number(1s and 0s) : ";
cin >> num;
bin = num;
Bnum = binaryCon(num);
cout << "The decimal equivalent of " << bin << " : " << Bnum << endl;
getchar();
return 0;
}
int binaryCon(int biNum)
{
long dec = 0, rem = 0, base = 1;
while (biNum > 0){
rem = biNum % 10;
dec = dec + rem * base;
base = base * 2;
biNum = biNum / 10;
}
return dec;
}