如何在wordpress中显示页面的有限内容
我有代码显示页面的如何在wordpress中显示页面的有限内容,wordpress,Wordpress,我有代码显示页面的内容和“标题”。我只想显示该页面内容的150个单词 这是我的密码 <?php $args = array( 'include' => 1319, 'post_type' => 'page', 'post_status' => 'publish' ); $mypages = get_pages($args); foreach($mypages as $page) { $content = $page->p
内容
和“标题”。我只想显示该页面内容的150个单词
这是我的密码
<?php
$args = array(
'include' => 1319,
'post_type' => 'page',
'post_status' => 'publish'
);
$mypages = get_pages($args);
foreach($mypages as $page)
{
$content = $page->post_content;
$content = apply_filters('the_content', $content);
?>
<div class="page_botheadingtop">
<?php echo $page->post_title ?>
</div>
<div class="page_botheadingmiddle">
<?php echo $page->post_content; ?>
</div>
<div class="page_botheadingbottom">
<a href="<?php echo get_page_link($page->ID) ?>">Read More..</a>
</div>
<?php
}
此代码显示id为1319的页面的所有内容。我只想显示150字,请提供建议
我将非常感谢你
我在等你的答复
谢谢使用
<?php
the_excerpt_max_charlength(140);
function the_excerpt_max_charlength($charlength) {
$excerpt = get_the_excerpt();
$charlength++;
if ( mb_strlen( $excerpt ) > $charlength ) {
$subex = mb_substr( $excerpt, 0, $charlength - 5 );
$exwords = explode( ' ', $subex );
$excut = - ( mb_strlen( $exwords[ count( $exwords ) - 1 ] ) );
if ( $excut < 0 ) {
echo mb_substr( $subex, 0, $excut );
} else {
echo $subex;
}
echo '[...]';
} else {
echo $excerpt;
}
}
?>
或
<?php
$my_excerpt = get_the_excerpt();
if ( $my_excerpt != '' ) {
// Some string manipulation performed
}
echo $my_excerpt; // Outputs the processed value to the page
?>