如何：WPF设计器与Prism绑定预览

如何说服Visual Studio（2017）中的WPF设计师在设计时预览Prism绑定结果？这些绑定在运行时工作，没有任何ViewModelLocator的特殊配置

使用此主窗口：

<Window x:Class="ViewModelLocator.Views.MainWindow"
    ...
        prism:ViewModelLocator.AutoWireViewModel="True"
        Title="{Binding Title}">
    <Grid>
        <TextBlock Text="{Binding Title}" />
    </Grid>
</Window>

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示例复制自：

似乎问题与Prim无关（尽管我希望prism能够提供自动解决方案）

只需像这样设置设计时数据上下文。这需要MainWindowViewModel实现一个无参数的构造函数来构建设计时数据

<Window x:Class="ViewModelLocator.Views.MainWindow"
        ...        
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:vm="clr-namespace:ViewModelLocator.ViewModels"
        mc:Ignorable="d"
        d:DataContext="{d:DesignInstance vm:MainWindowViewModel, IsDesignTimeCreatable=True}"

        prism:ViewModelLocator.AutoWireViewModel="True"
        Title="{Binding Title}">
    <Grid>
        <TextBlock Text="{Binding Title}" />
    </Grid>
</Window>

---

您可以投票支持与此相关的resharper错误：

<Window x:Class="ViewModelLocator.Views.MainWindow"
        ...        
        xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006"
        xmlns:d="http://schemas.microsoft.com/expression/blend/2008"
        xmlns:vm="clr-namespace:ViewModelLocator.ViewModels"
        mc:Ignorable="d"
        d:DataContext="{d:DesignInstance vm:MainWindowViewModel, IsDesignTimeCreatable=True}"

        prism:ViewModelLocator.AutoWireViewModel="True"
        Title="{Binding Title}">
    <Grid>
        <TextBlock Text="{Binding Title}" />
    </Grid>
</Window>