Xslt 通过XSL添加rowspan
我有以下xml:Xslt 通过XSL添加rowspan,xslt,Xslt,我有以下xml: <?xml version="1.0" encoding="ISO-8859-1"?> <Loci> <Locus> <Id>MTBC1726</Id> <Alleles> <Allele> <Name>1.0</Name> <Descr
<?xml version="1.0" encoding="ISO-8859-1"?>
<Loci>
<Locus>
<Id>MTBC1726</Id>
<Alleles>
<Allele>
<Name>1.0</Name>
<Description>No annotation provided</Description>
</Allele>
<Allele>
<Name>2.0</Name>
<Description>No annotation provided</Description>
</Allele>
</Alleles>
</Locus>
<Locus>
<Id>MTBC3142</Id>
<Alleles>
<Allele>
<Name>1.0</Name>
<Description>No annotation provided</Description>
</Allele>
</Alleles>
</Locus>
</Loci>
MTBC1726
1
没有提供注释
2
没有提供注释
MTBC3142
1
没有提供注释
我想创建以下结果:
在HTML中,如下所示:
<html>
<body>
<table border="1">
<tr>
<th>Locus</th>
<th>Allele</th>
<th>Description</th>
</tr>
<tr>
<td rowspan="2">MTBC1726</td>
<td>1.0</td>
<td >No annotation provided</td>
</tr>
<tr>
<td>2.0</td>
<td >No annotation provided</td>
</tr>
<tr>
<td >MTBC3142</td>
<td>1.0</td>
<td >No annotation provided</td>
</tr>
</table>
</body>
</html>
发生地
等位基因
描述
MTBC1726
1
没有提供注释
2
没有提供注释
MTBC3142
1
没有提供注释
我创建了以下XSL:
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html>
<body>
<table border="1">
<tr>
<th>Locus</th>
<th>Allele</th>
<th>Description</th>
</tr>
<xsl:for-each select="Loci/Locus">
<tr>
<td><xsl:value-of select="Id"/></td>
<xsl:for-each select="Alleles/Allele">
<td><xsl:value-of select="Name"/></td>
<td><xsl:value-of select="Description"/></td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
发生地
等位基因
描述
但这会生成这样一个表:
<html>
<body>
<table border="1">
<tr>
<th>Locus</th>
<th>Allele</th>
<th>Description</th>
</tr>
<tr>
<td rowspan="2">MTBC1726</td>
<td>1.0</td>
<td >No annotation provided</td>
</tr>
<tr>
<td>2.0</td>
<td >No annotation provided</td>
</tr>
<tr>
<td >MTBC3142</td>
<td>1.0</td>
<td >No annotation provided</td>
</tr>
</table>
</body>
</html>
因此,我的问题是:如何添加基于
节点数的行span
属性
<table border="1">
<tr>
<th>Locus</th>
<th>Allele</th>
<th>Description</th>
</tr>
<xsl:for-each select="Loci/Locus">
<xsl:for-each select="Alleles/Allele">
<tr>
<xsl:if test="position() = 1">
<td rowspan="{last()}">
<xsl:value-of select="ancestor::Locus[1]/Id"/>
</td>
</xsl:if>
<td><xsl:value-of select="Name"/></td>
<td><xsl:value-of select="Description"/></td>
</tr>
</xsl:for-each>
</xsl:for-each>
</table>
可以使用XSL count()函数定义变量,然后将该变量作为属性值输出:
<xsl:variable name="recordCount" select="count(Alleles/Allele)"/>
<td rowspan="{$recordCount}"><xsl:value-of select="Id"/></td>
您可以计算
等位基因的数量,并使用该值创建行范围。我还做了一个检查,以便在只有一个等位基因的情况下,不会添加rowspan=1
<xsl:template match="/">
<html>
<body>
<table border="1">
<tr>
<th>Locus</th>
<th>Allele</th>
<th>Description</th>
</tr>
<xsl:for-each select="Loci/Locus">
<tr>
<td>
<xsl:if test="count(Alleles/Allele) > 1">
<xsl:attribute name="rowspan">
<xsl:value-of select="count(Alleles/Allele)"/>
</xsl:attribute>
</xsl:if>
<xsl:value-of select="Id"/>
</td>
<xsl:for-each select="Alleles/Allele">
<td><xsl:value-of select="Name"/></td>
<td><xsl:value-of select="Description"/></td>
</xsl:for-each>
</tr>
</xsl:for-each>
</table>
</body>
</html>
</xsl:template>
发生地
等位基因
描述