XSLT将带有父节点的节点移动到每个父节点中';s具有给定属性的同级
我有以下源代码a.html:XSLT将带有父节点的节点移动到每个父节点中';s具有给定属性的同级,xslt,Xslt,我有以下源代码a.html: <html> <head> <title>title</title> </head> <body> <div class="a">a <div class="a1">a1</div> <div class="x" type="typea2">x <div class="x1"
<html>
<head>
<title>title</title>
</head>
<body>
<div class="a">a
<div class="a1">a1</div>
<div class="x" type="typea2">x
<div class="x1">x1</div>
</div>
<div class="a3">a3</div>
</div>
<div class="b">b_1
<div class="b1">b1_1</div>
<div class="b3">b3_11</div>
<div class="b3">b3_12</div>
<div class="b3">b3_13</div>
</div>
<div class="b">b_2
<div class="b1">b1_2</div>
<div class="b3">b3_21</div>
<div class="b3">b3_22</div>
<div class="b">b_3
<div class="b1">b1_3</div>
<div class="b3">b3_31</div>
<div class="b3">b3_32</div>
<div class="b3">b3_33</div>
<div class="b3">b3_34</div>
</div>
</body>
</html>
使用以下a.xslt:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!-- ignore x-inside-a -->
<xsl:template match="//div[@class='a']/div[@class='x']"/>
<!-- place the x-inside-a into each b after text() and b1 -->
<xsl:template match="div[@class='b']">
<xsl:copy>
<xsl:copy-of select="//div[@class='a']/div[@class='x']" />
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
然而,我没有得到想要的结果
我可以请求您的帮助吗?如果内部
div
始终存在,我会为它编写一个模板:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*" name="identity">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!-- ignore x-inside-a -->
<xsl:template match="div[@class='a']/div[@class='x']"/>
<!-- place the x-inside-a into each b after b1 -->
<xsl:template match="div[@class='b']/div[@class = 'b1']">
<xsl:call-template name="identity"/>
<xsl:copy-of select="//div[@class='a']/div[@class='x']" />
</xsl:template>
</xsl:stylesheet>
在
div class=“b”
中是否总是有一个div class=“b1”
?如果div class=“b1”
不存在,您想在哪里插入另一个div
。是的,div class=“b1”始终存在于div class=“b”中。
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!-- ignore x-inside-a -->
<xsl:template match="//div[@class='a']/div[@class='x']"/>
<!-- place the x-inside-a into each b after text() and b1 -->
<xsl:template match="div[@class='b']">
<xsl:copy>
<xsl:copy-of select="//div[@class='a']/div[@class='x']" />
<xsl:apply-templates />
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="node()|@*" name="identity">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
<!-- ignore x-inside-a -->
<xsl:template match="div[@class='a']/div[@class='x']"/>
<!-- place the x-inside-a into each b after b1 -->
<xsl:template match="div[@class='b']/div[@class = 'b1']">
<xsl:call-template name="identity"/>
<xsl:copy-of select="//div[@class='a']/div[@class='x']" />
</xsl:template>
</xsl:stylesheet>