在android中创建登录页面
我已经为我的应用程序创建了一个登录页面。当我在模拟器中运行时,如果密码和用户名匹配,它应该转到下一个屏幕,但当运行时,如果用户名和密码错误,应用程序将转到第二页,有人能建议吗在android中创建登录页面,android,Android,我已经为我的应用程序创建了一个登录页面。当我在模拟器中运行时,如果密码和用户名匹配,它应该转到下一个屏幕,但当运行时,如果用户名和密码错误,应用程序将转到第二页,有人能建议吗 EditText txtUserName; EditText txtPassword; Button btnLogin; Button btnCancel; /** Called when the activity is first created. */ @Override public void o
EditText txtUserName;
EditText txtPassword;
Button btnLogin;
Button btnCancel;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
txtUserName=(EditText)this.findViewById(R.id.txtUname);
txtPassword=(EditText)this.findViewById(R.id.txtPwd);
btnLogin=(Button)this.findViewById(R.id.btnLogin);
btnLogin.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
Intent myIntent = new Intent(v.getContext(), AddName.class);
startActivityForResult(myIntent, 0);
if((txtUserName.getText().toString()).equals(txtPassword.getText().toString())){
Toast.makeText(LoginappActivity.this, "Login Successful",Toast.LENGTH_LONG).show();
} else{
Toast.makeText(LoginappActivity.this, "Invalid Login",Toast.LENGTH_LONG).show();
}
}
});
}
}
}} 用您的代码替换此代码,这将非常有效
EditText txtUserName;
EditText txtPassword;
Button btnLogin;
Button btnCancel;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
txtUserName=(EditText)this.findViewById(R.id.txtUname);
txtPassword=(EditText)this.findViewById(R.id.txtPwd);
btnLogin=(Button)this.findViewById(R.id.btnLogin);
btnLogin.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if((txtUserName.getText().toString()).equals(txtPassword.getText().toString())){
Intent firstIntent = new Intent(v.getContext(), SecondActivity.class);
startActivity(firstIntent);
} else{
Intent secondtIntent = new Intent(v.getContext(),SecondActivity.class);
startActivity(secondIntent);
}
}
});
btnLogin=(Button)this.findViewById(R.id.btnLogin);
btnLogin.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if((txtUserName.getText().toString()).equals(txtPassword.getText().toString())){
Toast.makeText(LoginappActivity.this, "Login Successful",Toast.LENGTH_LONG).show();
Intent myIntent = new Intent(v.getContext(), AddName.class);
startActivity(myIntent);
} else{
Toast.makeText(LoginappActivity.this, "Invalid Login",Toast.LENGTH_LONG).show();
}
}
});
package com.app.NewProjectHttpDemo;
import java.io.InputStream;
import java.net.URL;
import java.util.ArrayList;
import android.content.Context;
import android.graphics.drawable.Drawable;
import android.view.LayoutInflater;
import android.view.View;
import android.view.ViewGroup;
import android.widget.ArrayAdapter;
import android.widget.ImageView;
import android.widget.TextView;
EditText txtUserName;
EditText txtPassword;
Button btnLogin;
Button btnCancel;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
txtUserName=(EditText)this.findViewById(R.id.txtUname);
txtPassword=(EditText)this.findViewById(R.id.txtPwd);
btnLogin=(Button)this.findViewById(R.id.btnLogin);
btnLogin.setOnClickListener(new OnClickListener() {
@Override
public void onClick(View v) {
if((txtUserName.getText().toString()).equals(txtPassword.getText().toString())){
Intent myIntent = new Intent(v.getContext(), AddName.class);
startActivityForResult(myIntent, 1);
Toast.makeText(LoginappActivity.this, "Login Successful",Toast.LENGTH_LONG).show();
} else{
Toast.makeText(LoginappActivity.this, "Invalid Login",Toast.LENGTH_LONG).show();
}
}
});
}
}