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在android中使用OAuth发送电子邮件而无需用户交互_Android_Oauth_Smtp - Fatal编程技术网

在android中使用OAuth发送电子邮件而无需用户交互

在android中使用OAuth发送电子邮件而无需用户交互,android,oauth,smtp,Android,Oauth,Smtp,我在尝试连接到smtp时遇到此错误 javax.mail.MessagingException: 334 eyJzdGF0dXMiOiI0MDAiLCJzY2hlbWVzIjoiQmVhcmVyIiwic2NvcGUiOiJodHRwczovL21haWwuZ29vZ2xlLmNvbS8ifQ== 这是我的密码 public class GMailOauthSender { private Session session; public SMTPTransport conne

我在尝试连接到smtp时遇到此错误

javax.mail.MessagingException: 334 eyJzdGF0dXMiOiI0MDAiLCJzY2hlbWVzIjoiQmVhcmVyIiwic2NvcGUiOiJodHRwczovL21haWwuZ29vZ2xlLmNvbS8ifQ==
这是我的密码

public class GMailOauthSender
{
    private Session session;

    public SMTPTransport connectToSmtp(String host, int port, String userEmail, String oauthToken, boolean debug) throws Exception {

        Properties props = new Properties();
        props.put("mail.smtp.starttls.enable", "true");
        props.put("mail.smtp.starttls.required", "true");
        props.put("mail.smtp.sasl.enable", "false");
        session = Session.getInstance(props);
        session.setDebug(debug);

        final URLName unusedUrlName = null;
        SMTPTransport transport = new SMTPTransport(session, unusedUrlName);
        // If the password is non-null, SMTP tries to do AUTH LOGIN.
        final String emptyPassword = null;
        transport.connect(host, port, userEmail, emptyPassword);

        byte[] response = String.format("user=%s\1auth=Bearer %s\1\1", userEmail, oauthToken).getBytes();
        response = BASE64EncoderStream.encode(response);

        transport.issueCommand("AUTH XOAUTH2 " + new String(response), 235);

        return transport;
    }

    public synchronized void sendMail(String subject, String body, String user, String oauthToken, String recipients) {
        try {
            SMTPTransport smtpTransport = connectToSmtp("smtp.gmail.com",587,user,oauthToken,true);

            MimeMessage message = new MimeMessage(session);
            DataHandler handler = new DataHandler(new ByteArrayDataSource(body.getBytes(), "text/plain"));   
            message.setSender(new InternetAddress(user));   
            message.setSubject(subject);   
            message.setDataHandler(handler);   

            if (recipients.indexOf(',') > 0)   
                message.setRecipients(Message.RecipientType.TO, InternetAddress.parse(recipients));   
            else  
                message.setRecipient(Message.RecipientType.TO, new InternetAddress(recipients));   

            smtpTransport.sendMessage(message, message.getAllRecipients());   
        } catch (Exception e) {
            Log.d("test", e.getMessage());
        }
    }
}
我从堆栈溢出的某个地方得到了这段代码。
任何帮助???

您收到的错误

eyJzdGF0dXMiOiI0MDAiLCJzY2hlbWVzIjoiQmVhcmVyIiwic2NvcGUiOiJodHRwczovL21haWwuZ29vZ2xlLmNvbS8ifQ==
使用Base64解码器解码到以下内容

{"status":"400","schemes":"Bearer","scope":"https://mail.google.com/"}
这最终意味着(与消息一样神秘)您正在使用的身份验证令牌已过期。您需要使它失效,然后获得一个新的(只需再次请求令牌)

您可以如下方式使令牌无效:

mAccountManager.invalidateAuthToken("con.google", mAuthenticationToken);

我希望这是有帮助的:)

试试这个,它可能会对你有所帮助。让我知道,即使你有任何问题。嗨,哈什穆克谢谢你的答复。这很好,但我想从用户已经在手机中设置的帐户发送电子邮件。在这种情况下,我如何在这里获取密码?这意味着谷歌播放Ac,在手机中设置Ac时使用密码?是的,完全正确。不,对不起,亲爱的,甚至让我们试着用另一种方式为你找到答案。