Android 2D阵列

我试图根据

单选按钮显示数组的内容。我用了两套按钮。按钮应指向我的阵列中的
[x，y]
。应显示数组的
字符串
值（使用
Toast
）

是的，我在这方面是新手，但我试着用很少的运气来区分几个类似的例子

public class MainActivity extends Activity {
    String[][] tipSize = {
            {"N/A","N/A","Pink","Lt Blue","Purple","Yellow","Brown","Orange","Tan","Blue","White","Beige"},
            {"N/A","Pink","Lt Blue","Purple","Yellow","Brown","Orange","Green","Tan","Blue","White","Beige"},
            {"N/A","N/A","Pink","Purple","Turquoise","Yellow","Green","Tan","Blue","White","Red","No Tip"},
            {"Pink","Lt Blue","Purple","Yellow","Orange","Green","Tan","Blue","Red","Beige","Gray","N/A"},
            {"Pink","Lt Plue","Purple","Orange","Green","Tan","Blue","White","Beige","Black","Gray","N/A"},
            {"Pink","Lt Blue","Yellow","Brown","Orange","Green","Tan","Blue","White","Beige","Black","N/A"},
            {"Pink","Lt Blue","Yellow","Brown","Tan","Blue","White","Red","Beige","Black","No Tip","N/A"},
            {"Pink","Lt Blue","Purple","Yellow","Orange","Green","Tan","Blue","Red","Beige","Gray","N/A"},
    };

private RadioGroup dispenser,ounce_pg;
private RadioButton disp,o_pg;
String tip = "";

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    Button finishBtn = (Button) findViewById(R.id.button1);
    finishBtn.setOnClickListener (new View.OnClickListener() {      
        @Override
        public void onClick(View v) {
            // TODO Auto-generated method stub
            MainActivity.this.showit(); 
        }
    });     
}

protected void showit() {
    // TODO Auto-generated method stub
    disp = (RadioButton) findViewById(R.id.dispenser);
    o_pg = (RadioButton) findViewById(R.id.ounce_pg);
    tip = String tipSize [disp,o_pg];
    // tip is the displayed answer (Color of tip), tipSize[][] is the Array, disp is RadioButton 1 - o_pg is Radio Button 2 values. 

    Toast.makeText(MainActivity(),tip,Toast.LENGTH_LONG).show();
}

}

这条线有很多问题：

 tip = String tipSize [disp,o_pg];

[disp，o_pg]
应该是
[disp][o_pg]
，因为访问2D数组是通过
数组[x][y]

String tipSize
没有意义，您不能在此处声明类型。如果你做了
（String）
这将是一个强制转换，这也没关系（但这将是多余的，因为你有一个
字符串
数组-从
字符串
强制转换到
字符串
没有任何作用）

disp
和
o_pg
应该是
int

这是因为在访问索引时，不能将对象传递给数组，数组不会“搜索”您。这意味着你需要弄清楚你想要进入什么位置，然后把它们传递出去。还要记住，索引从
0
开始，而不是从
1
开始

一个可编译的例子是：

tip = tipSize [0][0]; //first element of the first array ("N/A")

一种快速而肮脏的方法是创建一个简单的字符串数组，其中包含一个分隔字符串，该字符串将第二个值分组在一起，然后使用split函数，该函数本身返回一个字符串数组来获取各个值

String [] allTips = {"a;b;c", "d;e;f"};
String [] sometips = alltips[1].split(";")
String tip = sometips[2];

会导致字母
f
你的问题是什么？我知道语法是错误的，但我留下它是为了尝试显示我正在寻找的方向。感谢您的帮助。如果语法错误，您的编译器错误是什么？当RadioButton传递值时，是@id值还是您可以为每个单选按钮设置值，然后“case check”值？另外，值是作为字符串还是Int传递的？“输入RadioButton”或将其转换为字符串时遇到问题。@user2152750当RadioButton传递值时，请详细说明。什么时候点击？如果RadioButton是RadioGroup的一部分，则可以使用获取RadioButton的Id；如果RadioButton是单独的，则可以使用
OnClickListener
。然后，您必须比较id以确定您想要的位置（例如
if（R.id.button=view.getId（））String s=tipSize[0][0]；
此外，如果您发现我的答案有帮助，您应该阅读@user2152750。或者如果您需要进一步澄清（前提是您阅读了我的答案和我发布的链接），请留下评论。