如何在android中访问url返回数据

这是一个url地址。如何访问url返回数据？url需要返回json数据。 它可以访问返回数据。我想使用android HttpClient。怎么可能呢？

@Override
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new AsyncTask<Void,Void,Void>() {

    @Override
    protected Void doInBackground(Void... params) {
        // TODO Auto-generated method stub
        JSONObject jObject = getJSONfromURL("http://mascwt.oicp.net:7080/Monitoring/Data/getOrgData/");
        return null;
    }
}.execute();
}
  public JSONObject getJSONfromURL(String url) {

// initialize
InputStream is = null;
String result = "";
JSONObject jArray = null;

// http post
try {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost(url);
    HttpResponse response = httpclient.execute(httppost);
    HttpEntity entity = response.getEntity();
    is = entity.getContent();

} catch (Exception e) {
    Log.e("log_tag", "Error in http connection " + e.toString());
}

// convert response to string
try {
    BufferedReader reader = new BufferedReader(new InputStreamReader(
            is, "iso-8859-1"), 8);
    StringBuilder sb = new StringBuilder();
    String line = null;
    while ((line = reader.readLine()) != null) {
        sb.append(line + "\n");
    }
    is.close();
    result = sb.toString();
} catch (Exception e) {
    Log.e("log_tag", "Error converting result " + e.toString());
}

// try parse the string to a JSON object
try {
    jArray = new JSONObject(result);
} catch (JSONException e) {
    Log.e("log_tag", "Error parsing data " + e.toString());
}

return jArray;

创建时的公共void（Bundle savedInstanceState）{
super.onCreate（savedInstanceState）；
setContentView（R.layout.activity_main）；
新建异步任务（）{
@凌驾
受保护的Void doInBackground（Void…参数）{
//TODO自动生成的方法存根
JSONObject jObject=getJSONfromURL（“http://mascwt.oicp.net:7080/Monitoring/Data/getOrgData/");
返回null；
}
}.execute（）；
}
公共JSONObject getJSONfromURL（字符串url）{
//初始化
InputStream=null；
字符串结果=”；
JSONObject jArray=null；
//http post
试一试{
HttpClient HttpClient=新的DefaultHttpClient（）；
HttpPost HttpPost=新的HttpPost（url）；
HttpResponse response=httpclient.execute（httppost）；
HttpEntity=response.getEntity（）；
is=entity.getContent（）；
}捕获（例外e）{
e（“Log_标记”，“http连接错误”+e.toString（））；
}
//将响应转换为字符串
试一试{
BufferedReader reader=新的BufferedReader（新的InputStreamReader(
is，“iso-8859-1”），8）；
StringBuilder sb=新的StringBuilder（）；
字符串行=null；
而（（line=reader.readLine（））！=null）{
sb.追加（第+行“\n”）；
}
is.close（）；
结果=sb.toString（）；
}捕获（例外e）{
Log.e（“Log_标记”，“错误转换结果”+e.toString（））；
}
//尝试将字符串解析为JSON对象
试一试{
jArray=新的JSONObject（结果）；
}捕获（JSONException e）{
Log.e（“Log_标记”，“错误解析数据”+e.toString（））；
}
返回jArray；

}

看看这个：在这里，您将找到如何在android中加载json页面的答案

public class WebServices {
public JSONObject RequestUrl(String url) {
    JSONObject jsonResponse = null;
    try {
        DefaultHttpClient httpClient = new DefaultHttpClient();
        Log.v("URL request", "--->" + url);
        URI uri = new URI(url);
        HttpGet httpget = new HttpGet(uri);
        httpget.setHeader("Accept", "application/json");
        httpget.setHeader("Content-type", "application/json; charset=utf-8");
        HttpResponse response = httpClient.execute(httpget);
        HttpEntity responseEntity = response.getEntity();
        String changeTIDRec = EntityUtils.toString(responseEntity);
        System.out.println(changeTIDRec);
        jsonResponse = new JSONObject(changeTIDRec);
        Log.v("WebService", "Response : " + jsonResponse);
    } catch (Exception e) {
        e.printStackTrace();
    }
    return jsonResponse;
}}