Android 如何将一个对象传递给另一个活动?
我需要通过intent将一个类对象传递给另一个活动。这是我的班级代码:Android 如何将一个对象传递给另一个活动?,android,android-intent,android-activity,Android,Android Intent,Android Activity,我需要通过intent将一个类对象传递给另一个活动。这是我的班级代码: public class Model { private String Name; private ArrayList<Trim> trim; public String getName() { return Name; } public void setName(String Name) { this.Name = Na
public class Model
{
private String Name;
private ArrayList<Trim> trim;
public String getName()
{
return Name;
}
public void setName(String Name)
{
this.Name = Name;
}
public ArrayList<Trim> getTrim()
{
return trim;
}
public void setTrim(ArrayList<Trim> trim)
{
this.trim = trim;
}
}
公共类模型
{
私有字符串名称;
私人ArrayList trim;
公共字符串getName()
{
返回名称;
}
公共void集合名(字符串名)
{
this.Name=Name;
}
公共数组列表getTrim()
{
回位微调;
}
公共空间设置修剪(ArrayList修剪)
{
this.trim=修剪;
}
}
要将对象传递给另一个活动,您需要实现Parcelable
仔细复习。在这里,他们使用Hashmap存储值并将对象传递给另一个类
或
创建一个类,
ObjectA
。在这方面,我使用了所有setter和getter方法
package com.ParcableExample.org;
import android.os.Parcel;
import android.os.Parcelable;
/**
* A basic object that can be parcelled to
* transfer between objects.
*/
public class ObjectA implements Parcelable
{
private String strValue = null;
private int intValue = 0;
/**
* Standard basic constructor for non-parcel
* object creation.
*/
public ObjectA()
{
}
/**
*
* Constructor to use when re-constructing object
* from a parcel.
*
* @param in a parcel from which to read this object.
*/
public ObjectA(Parcel in)
{
readFromParcel(in);
}
/**
* Standard getter
*
* @return strValue
*/
public String getStrValue()
{
return this.strValue;
}
/**
* Standard setter
*
* @param strValue
*/
public void setStrValue(String strValue)
{
this.strValue = strValue;
}
/**
* Standard getter
*
* @return intValue
*/
public Integer getIntValue()
{
return this.intValue;
}
/**
* Standard setter
*
* @param strValue
*/
public void setIntValue(Integer intValue)
{
this.intValue = intValue;
}
@Override
public int describeContents()
{
return 0;
}
@Override
public void writeToParcel(Parcel dest, int flags)
{
// We just need to write each field into the
// parcel. When we read from parcel, they
// will come back in the same order
dest.writeString(this.strValue);
dest.writeInt(this.intValue);
}
/**
*
* Called from the constructor to create this
* object from a parcel.
*
* @param in parcel from which to re-create object.
*/
public void readFromParcel(Parcel in)
{
// We just need to read back each
// field in the order that it was
// written to the parcel
this.strValue = in.readString();
this.intValue = in.readInt();
}
/**
*
* This field is needed for Android to be able to
* create new objects, individually or as arrays.
*
* This also means that you can use use the default
* constructor to create the object and use another
* method to hyrdate it as necessary.
*/
@SuppressWarnings("unchecked")
public static final Parcelable.Creator CREATOR = new Parcelable.Creator()
{
@Override
public ObjectA createFromParcel(Parcel in)
{
return new ObjectA(in);
}
@Override
public Object[] newArray(int size)
{
return new ObjectA[size];
}
};
}
然后创建一个用于将对象发送到另一个活动的活动
package com.ParcableExample.org;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
public class ParcableExample extends Activity
{
private Button btnClick;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
initControls();
}
private void initControls()
{
btnClick = (Button)findViewById(R.id.btnClick);
btnClick.setOnClickListener(new OnClickListener()
{
@Override
public void onClick(View arg0)
{
ObjectA obj = new ObjectA();
obj.setIntValue(1);
obj.setStrValue("Chirag");
Intent i = new Intent(ParcableExample.this,MyActivity.class);
i.putExtra("com.package.ObjectA", obj);
startActivity(i);
}
});
}
}
现在,最后让另一个活动读取对象并从中获取值
package com.ParcableExample.org;
import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
public class MyActivity extends Activity
{
protected void onCreate(Bundle savedInstanceState)
{
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
Bundle bundle = getIntent().getExtras();
ObjectA obj = bundle.getParcelable("com.package.ObjectA");
Log.i("---------- Id ",":: "+obj.getIntValue());
Log.i("---------- Name ",":: "+obj.getStrValue());
}
}
您的类应该实现
Parcelable
接口,然后您可以使用以下方法将其发送到另一个活动
:
MyClass myObject;
//...
intent=new Intent(this, MyAnotherActivity.class);
intent.putExtra("mydata", (Parcelable )myObject);
this.startActivity(intent);
您需要在
模型
类中实现可序列化
。然后,要将模型
对象从源活动
传递到目标活动
,请在源活动
中使用以下代码:
Model objModel = new Model();
Intent modelActivity = (Model.this, detail.class);
intent.putExtra("ModelObject", objModel);
Model modelObject = getIntent().getSerializableExtra("ModelObject");
而目标活动中的此代码
:
Model objModel = new Model();
Intent modelActivity = (Model.this, detail.class);
intent.putExtra("ModelObject", objModel);
Model modelObject = getIntent().getSerializableExtra("ModelObject");
这个密码里有什么?发布活动代码可能重复:使用Parcelable或serializable实现。嗨,谢谢你的回复。。但当在目标活动中接收到与语句中的错误相同的对象时。。。model=this.getIntent().getSerializableExtra(“ModelClass”);相同的错误或logcat输出是什么?那么问题出在代码中。好好检查一下。您应该编写:modelmodelobject=getIntent().getSerializableExtra(“modelObject”);是的,我写了和你描述的相同的代码。。。语法错误是强制转换错误。更改模型对象是可序列化的…我还实现了串行。。在我的类模型中。根据您的上述注释和此注释,您可以尝试以下操作:ModelModelObject=(Model)getIntent().getSerializableExtra(“modelObject”);