Android 从url获取空xml
我试图从url获取xml输出,但得到的却是空xml。但是,如果我试图在浏览器上执行该url,它会得到我的响应……这是我的代码Android 从url获取空xml,android,xml,web-services,http,Android,Xml,Web Services,Http,我试图从url获取xml输出,但得到的却是空xml。但是,如果我试图在浏览器上执行该url,它会得到我的响应……这是我的代码 signup.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View arg0) { String us = username.getText().toString(); S
signup.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View arg0) {
String us = username.getText().toString();
String na = name.getText().toString();
String pa = password.getText().toString();
String rep = repass.getText().toString();
String e = email.getText().toString();
if (us.equals("") || na.equals("") || pa.equals("")
|| rep.equals("") || e.equals("")) {
Toast.makeText(getApplicationContext(), "Fill All Entries",
Toast.LENGTH_SHORT).show();
} else {
if (pa.equals(rep)) {
// xml_ajax_register(us, na, pa, e);
String url = "http://localhost:9090/plugins/userService/userservice?type="
+ "add&secret=0LRF2i8I&username="
+ us
+ "&password="
+ pa
+ "&name="
+ na
+ "&email="
+ e;
System.out.println("URL IS "+url);
String xml = parser.getXmlFromUrl(url);
// Document doc=parser.getDomElement(xml);
//
// NodeList nl=doc.getElementsByTagName("result");
System.out.println("XML Is " + xml);
} else {
Toast.makeText(getApplicationContext(),
"PassWord Doesn't Match", Toast.LENGTH_SHORT)
.show();
}
}
// String xml = getXmlFromUrl(url);
}
});
我的xml解析器类是
public class XMLParser {
// constructor
public XMLParser() {
}
/**
* Getting XML from URL making HTTP request
* @param url string
* */
public String getXmlFromUrl(String url) {
String xml = null;
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpGet httpGet = new HttpGet(url);
HttpResponse httpResponse = httpClient.execute(httpGet);
HttpEntity httpEntity = httpResponse.getEntity();
xml = EntityUtils.toString(httpEntity);
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
// return XML
return xml;
}
/**
* Getting XML DOM element
* @param XML string
* */
public Document getDomElement(String xml){
Document doc = null;
DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance();
try {
DocumentBuilder db = dbf.newDocumentBuilder();
InputSource is = new InputSource();
is.setCharacterStream(new StringReader(xml));
doc = db.parse(is);
} catch (ParserConfigurationException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (SAXException e) {
Log.e("Error: ", e.getMessage());
return null;
} catch (IOException e) {
Log.e("Error: ", e.getMessage());
return null;
}
return doc;
}
/** Getting node value
* @param elem element
*/
public final String getElementValue( Node elem ) {
Node child;
if( elem != null){
if (elem.hasChildNodes()){
for( child = elem.getFirstChild(); child != null; child = child.getNextSibling() ){
if( child.getNodeType() == Node.TEXT_NODE ){
return child.getNodeValue();
}
}
}
}
return "";
}
/**
* Getting node value
* @param Element node
* @param key string
* */
public String getValue(Element item, String str) {
NodeList n = item.getElementsByTagName(str);
return this.getElementValue(n.item(0));
}
提前谢谢 XML加载代码中可能出现异常,但由于处理异常的方式,它返回null。您只打印堆栈跟踪,但这会将xml保留为null。您看到打印的任何输出吗?是的,我的字符串xml在我的输出上返回null。您可以在调试模式下运行代码吗?并查看在哪里遇到空指针异常。它可能在任何地方,可能在美国,na,pa,e。您确定在调用parser.getXmlFromUrl(url)之前正确地生成了url吗?您能确认。。。