Android 由于URL中有空格，无法下载图像

我有一个从服务器下载图像并在imageview中显示的应用程序。这在大多数情况下有效，但并不总是有效。当url中有空格时，它似乎不起作用。我得到的错误是

java.lang.RuntimeException:java.io.FileNotFoundException:

我已经尝试了许多不同的方法来尝试和编码的网址，但没有成功到现在为止

这是我正在使用的类

private URL url;
Bitmap bitmap;

public ImageDownloader() {

}//constructor


public Drawable getImage(String urlString) throws IOException{
    Log.i("url", urlString);
    url = new URL(urlString);
    InputStream is = url.openStream();
    Bitmap bitmap = BitmapFactory.decodeStream(new FlushedInputStream(is));
    Drawable image = new BitmapDrawable(bitmap);
    return image;

 }//getImage

static class FlushedInputStream extends FilterInputStream {
    public FlushedInputStream(InputStream inputStream) {
        super(inputStream);
    }

    @Override
    public long skip(long n) throws IOException {
        long totalBytesSkipped = 0L;
        while (totalBytesSkipped < n) {
            long bytesSkipped = in.skip(n - totalBytesSkipped);
            if (bytesSkipped == 0L) {
                  int bytee = read();
                  if (bytee < 0) {
                      break;  // we reached EOF
                  } else {
                      bytesSkipped = 1; // we read one byte
                  }
           }
            totalBytesSkipped += bytesSkipped;
        }
        return totalBytesSkipped;
    }
}


public Bitmap getBitmap(String urlString) {
    try {
        //String s = Uri.encode(urlString);
        url = new URL(urlString);
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    HttpURLConnection conn = null;
    try {
        conn = (HttpURLConnection) url.openConnection();
           conn.setRequestProperty("User-agent", "Mozilla/4.0");
           conn.connect();

    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    InputStream in = null;
    try {
        in = conn.getInputStream();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return bitmap = BitmapFactory.decodeStream(in);



}

私有URL；
位图；
公共图像下载程序（）{
}//建造师
公共可绘制getImage（字符串urlString）引发IOException{
Log.i（“url”，urlString）；
url=新url（url字符串）；
InputStream=url.openStream（）；
位图位图=BitmapFactory.decodeStream（新的FlushedInputStream（is））；
可绘制图像=新的位图可绘制（位图）；
返回图像；
}//获取图像
静态类FlushedInputStream扩展FilterInputStream{
公共FlushedInputStream（InputStream InputStream）{
超级（输入流）；
}
@凌驾
公共长跳过（长n）引发IOException{
长的总重量=0升；
while（totalBytesSkipped

getImage和getBitmap都有相同的错误

下面是一个我正在使用的url示例

private URL url;
Bitmap bitmap;

public ImageDownloader() {

}//constructor


public Drawable getImage(String urlString) throws IOException{
    Log.i("url", urlString);
    url = new URL(urlString);
    InputStream is = url.openStream();
    Bitmap bitmap = BitmapFactory.decodeStream(new FlushedInputStream(is));
    Drawable image = new BitmapDrawable(bitmap);
    return image;

 }//getImage

static class FlushedInputStream extends FilterInputStream {
    public FlushedInputStream(InputStream inputStream) {
        super(inputStream);
    }

    @Override
    public long skip(long n) throws IOException {
        long totalBytesSkipped = 0L;
        while (totalBytesSkipped < n) {
            long bytesSkipped = in.skip(n - totalBytesSkipped);
            if (bytesSkipped == 0L) {
                  int bytee = read();
                  if (bytee < 0) {
                      break;  // we reached EOF
                  } else {
                      bytesSkipped = 1; // we read one byte
                  }
           }
            totalBytesSkipped += bytesSkipped;
        }
        return totalBytesSkipped;
    }
}


public Bitmap getBitmap(String urlString) {
    try {
        //String s = Uri.encode(urlString);
        url = new URL(urlString);
    } catch (MalformedURLException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }
    HttpURLConnection conn = null;
    try {
        conn = (HttpURLConnection) url.openConnection();
           conn.setRequestProperty("User-agent", "Mozilla/4.0");
           conn.connect();

    } catch (IOException e1) {
        // TODO Auto-generated catch block
        e1.printStackTrace();
    }

    InputStream in = null;
    try {
        in = conn.getInputStream();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    return bitmap = BitmapFactory.decodeStream(in);



}

---

URL编码将字符转换为可通过Internet传输的格式。例如，空间编码为%20

您可以在中找到整个表。

尝试此代码段

String songThumbUrl = "Image URL";
        try {
        URL thumbURL = new URL(songThumbUrl);
        try {
            URLConnection urlConnection = thumbURL.openConnection();
            urlConnection.connect();

            InputStream inputStream = urlConnection.getInputStream();
            BufferedInputStream bufferedInputStream = new BufferedInputStream(inputStream);
            Bitmap bitmap = BitmapFactory.decodeStream(bufferedInputStream);
            songThumbImageView.setImageBitmap(bitmap);

            bufferedInputStream.close();
            inputStream.close();

        } catch (IOException ioe) {
            System.out.println("My Exception :" + ioe);
            ioe.printStackTrace();
        }
    } catch (MalformedURLException mue) {
        System.out.println("My Exception :" + mue);
        mue.printStackTrace();
    }   

---

这是一个奇怪的问题。我试着用正常的方式编码，但还是出现了同样的错误。我检查正在发送的URL，并且空间已更改为“%20”。最后，由于绝望，我决定自己将空格改为“%20”，而不是编码。这就解决了问题。虽然不是最优雅的解决方案，但它确实奏效了

        String url1 = json.getString("app_imagepath");
        String url = url1.replace(" ", "%20");

---

这应该行得通。在浏览器中用%20而不是空格键入url，然后看看会发生什么。jiduvah，编码后，url中应该没有更多的空格。这与我的getBitmap（）方法非常相似，它也有相同的问题？我猜投反对票的人没有测试代码