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Android 通过PHP连接到MySQL,JSON错误_Android - Fatal编程技术网

Android 通过PHP连接到MySQL,JSON错误

Android 通过PHP连接到MySQL,JSON错误,android,Android,我编写了一个simpe PHP脚本,用于打印JSONECODE$输出。它输出带有前导和结尾[]的JSON。当我通过Emulator运行我的Android程序时,它声明:JSONObject文本必须在[…]的字符1处以“{”开头,然后列出我的JSON,因此我知道它获取数据,解码过程存在一个问题,即它没有删除这些方括号。下面是将错误抛出日志的函数: public class JSONfunctions { public static JSONObject getJSONfromURL(Str

我编写了一个simpe PHP脚本,用于打印JSONECODE$输出。它输出带有前导和结尾[]的JSON。当我通过Emulator运行我的Android程序时,它声明:JSONObject文本必须在[…]的字符1处以“{”开头,然后列出我的JSON,因此我知道它获取数据,解码过程存在一个问题,即它没有删除这些方括号。下面是将错误抛出日志的函数:

   public class JSONfunctions {

public static JSONObject getJSONfromURL(String url){
    InputStream is = null;
    String result = "";
    JSONObject jArray = null;

    //http post
    try{
            HttpClient httpclient = new DefaultHttpClient();
            HttpPost httppost = new HttpPost(url);
            HttpResponse response = httpclient.execute(httppost);
            HttpEntity entity = response.getEntity();
            is = entity.getContent();

    }catch(Exception e){
            Log.e("log_tag", "Error in http connection "+e.toString());
    }

  //convert response to string
    try{
            BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
            }
            is.close();
            result=sb.toString();
    }catch(Exception e){
            Log.e("log_tag", "Error converting result "+e.toString());
    }

    try{

        jArray = new JSONObject(result);            
    }catch(JSONException e){
            Log.e("log_tag", "Error parsing data "+e.toString());
    }

    return jArray;
}

}

听起来您的JSon响应像:[{'name':'value'},…]

JSon对象必须以{开头,如错误消息所示。它应该是: {'my_array':[……]}


然后您可以编写:new JSONObject.getJSONArraymy_array;

,但是PHP中默认的printjsonencode$output;的格式没有标题和方括号,无法更改。