Android ArrayAdapter错误

这是我的密码。 我在尝试获取查询结果时出错

（07-04 08:31:01.811:E/CursorWindow（5090）：无法从包含1行3列的CursorWindow中读取第0行第1列。）

我真的不知道该怎么办。 谢谢你的帮助

private void Bul(String CepTEL) {
    try
    {
        ArrayAdapter<String> ArrayAdapter2 = new ArrayAdapter<String>(Search.this,
                            android.R.layout.select_dialog_singlechoice);
        String[] sutunlar= {"NAME","LASTNAME","JOB","BDAY","ADDRESS","EMAIL","MOBILETEL","HOMETEL","WORKTEL"};
        SQLiteDatabase db= v1.getReadableDatabase();

        Cursor okunanlar=db.query("CUSTOMER",sutunlar,"MOBILETEL=?", new String[] {CepTEL},null,null,null);
        String NAME="";
        String LASTNAME="";
        String JOB="";
        String BDAY="";
        String ADDRESS="";
        String EMAIL="";
        String MOBILETEL="";
        String HOMETEL="";
        String WORKTEL="";

        while(okunanlar.moveToFirst())
        {
            NAME=okunanlar.getString(okunanlar.getColumnIndex(NAME));
            LASTNAME=okunanlar.getString(okunanlar.getColumnIndex(LASTNAME));
            JOB=okunanlar.getString(okunanlar.getColumnIndex(JOB));
            BDAY=okunanlar.getString(okunanlar.getColumnIndex(BDAY));
            ADDRESS=okunanlar.getString(okunanlar.getColumnIndex(ADDRESS));
            EMAIL=okunanlar.getString(okunanlar.getColumnIndex(EMAIL));
            MOBILETEL=okunanlar.getString(okunanlar.getColumnIndex(MOBILETEL));
            HOMETEL=okunanlar.getString(okunanlar.getColumnIndex(HOMETEL));
            WORKTEL=okunanlar.getString(okunanlar.getColumnIndex(WORKTEL));     
            ArrayAdapter2.add(NAME+"\n"+LASTNAME+"\n"+JOB+"\n"+BDAY+"\n"+ADDRESS+"\n"+EMAIL+"\n"+MOBILETEL+"\n"+HOMETEL+"\n"+WORKTEL);
        }
        cekilenleriGoster(ArrayAdapter2);
    }

    catch(Exception e)
    {
        Toast.makeText(getApplicationContext(),"Bilgiler girilirken hata oluştu.",Toast.LENGTH_LONG).show();
    }               
}

private void Bul（字符串CepTEL）{
尝试
{
ArrayAdapter ArrayAdapter2=新的ArrayAdapter（Search.this，
android.R.layout.select\u dialog\u singlechoice）；
String[]sutunlar={“NAME”、“LASTNAME”、“JOB”、“BDAY”、“ADDRESS”、“EMAIL”、“MOBILETEL”、“HOMETEL”、“WORKTEL”}；
SQLiteDatabase db=v1.getReadableDatabase（）；
游标okunalar=db.query（“CUSTOMER”，sutunlar，“MOBILETEL=？”，新字符串[]{CepTEL}，null，null，null）；
字符串名称=”；
字符串LASTNAME=“”；
字符串JOB=“”；
字符串BDAY=“”；
字符串地址=”；
字符串EMAIL=“”；
字符串MOBILETEL=“”；
字符串HOMETEL=“”；
字符串WORKTEL=“”；
while（okunalar.moveToFirst（））
{
NAME=okunalar.getString（okunalar.getColumnIndex（NAME））；
LASTNAME=okunalar.getString（okunalar.getColumnIndex（LASTNAME））；
JOB=okunalar.getString（okunalar.getColumnIndex（JOB））；
BDAY=okunalar.getString（okunalar.getColumnIndex（BDAY））；
ADDRESS=okunalar.getString（okunalar.getColumnIndex（ADDRESS））；
EMAIL=okunalar.getString（okunalar.getColumnIndex（EMAIL））；
MOBILETEL=okunalar.getString（okunalar.getColumnIndex（MOBILETEL））；
HOMETEL=okunalar.getString（okunalar.getColumnIndex（HOMETEL））；
WORKTEL=okunalar.getString（okunalar.getColumnIndex（WORKTEL））；
ArrayAdapter2.add（NAME+“\n”+LASTNAME+“\n”+JOB+“\n”+BDAY+“\n”+地址+“\n”+电子邮件+“\n”+移动电话+“\n”+家庭电话+“\n”+工作电话）；
}
cekilenleriGoster（ArrayaAdapter2）；
}
捕获（例外e）
{
Toast.makeText（getApplicationContext（），“Bilgiler Girilrken hata oluştu.”，Toast.LENGTH_LONG.show（）；
}               
}

您正试图使用名为空字符串的列的索引访问

光标的数据。噢，谢谢。NAME=okunalar.getString（okunalar.getColumnIndex（“NAME”）；它一定是这样的，而且很有效。