在Android中以片段形式显示数据
我试图显示来自SQLite的数据,并在片段的listview中显示它。这是我的代码,当我运行它时,它会自动关闭。此代码在我的主要活动中在Android中以片段形式显示数据,android,android-fragments,android-sqlite,Android,Android Fragments,Android Sqlite,我试图显示来自SQLite的数据,并在片段的listview中显示它。这是我的代码,当我运行它时,它会自动关闭。此代码在我的主要活动中 public static class ListDoctorFragment extends Fragment { ListView list; DataDB data = new DataDB(); ArrayAdapter<String> listAdapter; public ListDoctorF
public static class ListDoctorFragment extends Fragment {
ListView list;
DataDB data = new DataDB();
ArrayAdapter<String> listAdapter;
public ListDoctorFragment() {
}
@Override
public View onCreateView(LayoutInflater inflater, ViewGroup container, Bundle savedInstanceState) {
final View view = inflater.inflate(R.layout.listdoctor, container, false);
ArrayList<String> names = new ArrayList<String>();
try {
names = data.getDoctorlistDB(getActivity());
} catch (SQLException e) {
e.printStackTrace();
}
listAdapter = new ArrayAdapter<String>(getActivity(), R.layout.support_simple_spinner_dropdown_item, names);
// set the adapter
list.setAdapter(listAdapter);
return view;
}
}
公共静态类ListDoctorFragment扩展了片段{
列表视图列表;
DataDB data=新的DataDB();
阵列适配器;
公共列表doctorfragment(){
}
@凌驾
CreateView上的公共视图(布局、充气机、视图组容器、捆绑包保存状态){
最终视图=充气机。充气(R.layout.listdoctor,容器,假);
ArrayList name=新的ArrayList();
试一试{
name=data.getDoctorlistDB(getActivity());
}捕获(SQLE异常){
e、 printStackTrace();
}
listAdapter=new ArrayAdapter(getActivity(),R.layout.support\u simple\u spinner\u dropdown\u item,names);
//设置适配器
list.setAdapter(listAdapter);
返回视图;
}
}
您的“ListView列表”未初始化。一定是这样的:
list = (ListView) view.findViewById(R.id.listview);