Android中的倾斜矩阵

我在做Android项目。我正在使用View类使用画布和矩阵绘制位图

如何使矩阵倾斜？像这样：

class V extends View {

    private Bitmap b;
    private Matrix m;

    public V(Context context) {
        super(context);
        b = BitmapFactory.decodeResource(getResources(), R.drawable.layer0);
        m = new Matrix();
    }

    @Override
    protected void onSizeChanged(int w, int h, int oldw, int oldh) {
        int bw = b.getWidth();
        int bh = b.getHeight();
        float[] src = {0, 0, 0, bh, bw, bh, bw, 0};
        int DX = 100;
        float[] dst = {0 + DX, 0, 0, h, w, h, w - DX, 0};
        m.setPolyToPoly(src, 0, dst, 0, 4);
    }

    @Override
    protected void onDraw(Canvas canvas) {
        canvas.drawBitmap(b, m, null);
    }
}

我正在使用此代码，但它不起作用：

float[] src=new float[]{0,0,0,1,1,1,1,0};
float[] dst=new float[]{0.2f,0,0,1,1,1,0.8f,0};
Paint paint = new Paint();
matrix.reset();     
matrix.postTranslate(-width / 2.0f, -height / 2.0f);        
matrix.postRotate(0/*(float)(angle*180/Math.PI) ,-width / 2.0f + 50, -height / 2.0f +50*/);
matrix.postScale(scale, scale); 
matrix.setPolyToPoly(src, 0, dst, 0, 4);
matrix.postTranslate(position.getX(), position.getY());             
canvas.drawBitmap(bitmap, matrix, paint);
canvas.concat(matrix);

---

使用类似以下内容：

class V extends View {

    private Bitmap b;
    private Matrix m;

    public V(Context context) {
        super(context);
        b = BitmapFactory.decodeResource(getResources(), R.drawable.layer0);
        m = new Matrix();
    }

    @Override
    protected void onSizeChanged(int w, int h, int oldw, int oldh) {
        int bw = b.getWidth();
        int bh = b.getHeight();
        float[] src = {0, 0, 0, bh, bw, bh, bw, 0};
        int DX = 100;
        float[] dst = {0 + DX, 0, 0, h, w, h, w - DX, 0};
        m.setPolyToPoly(src, 0, dst, 0, 4);
    }

    @Override
    protected void onDraw(Canvas canvas) {
        canvas.drawBitmap(b, m, null);
    }
}

更新以保持图像纵横比：

    @Override
    protected void onSizeChanged(int w, int h, int oldw, int oldh) {
        int bw = b.getWidth();
        int bh = b.getHeight();
        RectF src = new RectF(0, 0, bw, bh);
        RectF dst = new RectF(0, 0, w, h);
        m.setRectToRect(src, dst, ScaleToFit.CENTER);

        float[] pts = {0, 0, 0, bh, bw, bh, bw, 0, 0, 0, 0, 0, 0, 0, 0, 0};
        m.mapPoints(pts, 8, pts, 0, 4);
        int DX = 40;
        pts[8] += DX;
        pts[14] -= DX;
        m.setPolyToPoly(pts, 0, pts, 8, 4);
    }

---

Matrix.SetPolyTopology谢谢你的回复，但是你能用一个简单的例子来解释这个方法和它的参数吗？使用src作为0,0,0,1,1,1,1,1,1,0,0,0,1,1,1,0.8,0，例如dst 0.2,0,0,0，1,1,1,0.8,0，请查看上面的代码，哪里是错误的？用一个工作代码查看我的答案谢谢，我明天会测试它，因为我现在没有设备，我会告诉你结果是什么。查看更新以保持图像纵横比