Android 在SQL数据库的一行中插入ArrayList

在我的食谱日记中，我有3节课，Recipe.class：

public Recipe(String title, String firstImage, String secondImage, String thirdImage, String instructions, int targetPeople, int time, int calories, ArrayList<Ingredient> ingredients, ArrayList<Tag> tags) {

    this.title = title;
    this.firstImage = firstImage;
    this.secondImage = secondImage;
    this.thirdImage = thirdImage;
    this.instructions = instructions;
    this.targetPeople = targetPeople;
    this.time = time;
    this.calories = calories;
    this.ingredients = ingredients;
    this.tags = tags;
}

和Tag.class：

public Tag(String tag_name) {

    this.tag_name = tag_name;

}

当我保存一个新配方时，我使用两个for循环来存储标签和配料，每个标签和配料都被添加到相应的ArrayList中，以将更多配料和标签链接到同一配方，如下所示：

for (int c=0; c < countTags; c++) {
           childChipView = (Chip) chipTagGroup.getChildAt(c);
           childTextViewTag = childChipView.findViewById(R.id.chip_item);
        childTag = childTextViewTag.getText().toString();
        newTag = new Tag(childTag);
        dbHelper.insertTag(newTag);
        tags.add(newTag);
    }

    // ingredients fields settings
    for (int d=0; d<countIngredients; d++) {
        childViewIng = parentIngredientLayout.getChildAt(d);
        childTextViewI = childViewIng.findViewById(R.id.ingredientsField);
        childTextViewQ = childViewIng.findViewById(R.id.quantityField);
        childIngredient = childTextViewI.getText().toString();
        childQuantity = Integer.parseInt(childTextViewQ.getText().toString());
        newIngredient = new Ingredient(childIngredient, childQuantity);
        dbHelper.insertIngredient(newIngredient);
        ingredients.add(newIngredient);
    }

---

之后，我存储在DB配方表、配料表、标签表的三个对应表中。我的问题是，如何将这两个ArrayList存储在RECIPE_表中？我想要，即，在该表的同一行中，标题、说明、时间、卡路里等以及两个ArrayList

您不应该在一行中插入整个数组，因为这违反了1NF，尝试将其拆分为两个表

根据定义ArrayList将是数据库中具有一对多关系的另一个表。。。当然，您可以序列化ArrayList并将其存储为字符串，但这会很尴尬，因此您建议我创建一个RECIPE_Component表和RECIPE_TAG表，以将ArrayList与同一个RECIPE关联？RECIPES ID、Name。。。TAGSID，Name，。。IngreditSID，名称，。。配方\u TAGSRecipeID，TagID配方\u IngCreditsRecipeId，IngCreditId。。。这就是大多数程序员使用关系数据库的方式

for (int c=0; c < countTags; c++) {
           childChipView = (Chip) chipTagGroup.getChildAt(c);
           childTextViewTag = childChipView.findViewById(R.id.chip_item);
        childTag = childTextViewTag.getText().toString();
        newTag = new Tag(childTag);
        dbHelper.insertTag(newTag);
        tags.add(newTag);
    }

    // ingredients fields settings
    for (int d=0; d<countIngredients; d++) {
        childViewIng = parentIngredientLayout.getChildAt(d);
        childTextViewI = childViewIng.findViewById(R.id.ingredientsField);
        childTextViewQ = childViewIng.findViewById(R.id.quantityField);
        childIngredient = childTextViewI.getText().toString();
        childQuantity = Integer.parseInt(childTextViewQ.getText().toString());
        newIngredient = new Ingredient(childIngredient, childQuantity);
        dbHelper.insertIngredient(newIngredient);
        ingredients.add(newIngredient);
    }