如果没有数组名,如何编写Android Json解析
} 我的问题是如何将这些代码编辑到另一个url。我的json url在这里: 如您所见,没有数组名称。我该怎么办?欢迎使用任何帮助如果没有数组名,如何编写Android Json解析,android,arrays,json,parsing,Android,Arrays,Json,Parsing,} 我的问题是如何将这些代码编辑到另一个url。我的json url在这里: 如您所见,没有数组名称。我该怎么办?欢迎使用任何帮助 package info.androidhive.jsonparsing; import android.util.Log; import java.io.BufferedInputStream; import java.io.BufferedReader; import java.io.IOException; import java.io.InputStre
package info.androidhive.jsonparsing;
import android.util.Log;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.ProtocolException;
import java.net.URL;
public class HttpHandler {
private static final String TAG = HttpHandler.class.getSimpleName();
public HttpHandler() {
}
public String makeServiceCall(String reqUrl) {
String response = null;
try {
URL url = new URL(reqUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
// read the response
InputStream in = new BufferedInputStream(conn.getInputStream());
response = convertStreamToString(in);
} catch (MalformedURLException e) {
Log.e(TAG, "MalformedURLException: " + e.getMessage());
} catch (ProtocolException e) {
Log.e(TAG, "ProtocolException: " + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "IOException: " + e.getMessage());
} catch (Exception e) {
Log.e(TAG, "Exception: " + e.getMessage());
}
return response;
}
private String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line).append('\n');
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
无需姓名。使用
package info.androidhive.jsonparsing;
import android.util.Log;
import java.io.BufferedInputStream;
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.ProtocolException;
import java.net.URL;
public class HttpHandler {
private static final String TAG = HttpHandler.class.getSimpleName();
public HttpHandler() {
}
public String makeServiceCall(String reqUrl) {
String response = null;
try {
URL url = new URL(reqUrl);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setRequestMethod("GET");
// read the response
InputStream in = new BufferedInputStream(conn.getInputStream());
response = convertStreamToString(in);
} catch (MalformedURLException e) {
Log.e(TAG, "MalformedURLException: " + e.getMessage());
} catch (ProtocolException e) {
Log.e(TAG, "ProtocolException: " + e.getMessage());
} catch (IOException e) {
Log.e(TAG, "IOException: " + e.getMessage());
} catch (Exception e) {
Log.e(TAG, "Exception: " + e.getMessage());
}
return response;
}
private String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line;
try {
while ((line = reader.readLine()) != null) {
sb.append(line).append('\n');
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
不需要名字。还有一个简单的解决方案。您可以使用GoogleGSON库解析json。您所要做的就是根据json格式i-e变量名创建一个类,该变量名与json字符串/文件中json对象的名称相同 还有一个简单的解决方案。您可以使用GoogleGSON库解析json。您所要做的就是根据json格式i-e变量名创建一个类,该变量名与json字符串/文件中json对象的名称相同 非常简单,只需像下面这样直接获取JSONArray对象: `
@覆盖
受保护的Void doInBackground(Void…arg0){
HttpHandler sh=新的HttpHandler();
//向url发出请求并获得响应
字符串jsonStr=sh.makeServiceCall(url);
Log.e(标签,“来自url的响应:+jsonStr”);
if(jsonStr!=null){
试一试{
//获取JSON数组节点
JSONArray联系人=新的JSONArray(jsonStr);
//通过所有触点循环
对于(int i=0;ivalue
联系人:put(“id”,id);
联系人。填写(“姓名”,姓名);
联系方式。放置(“电子邮件”,电子邮件);
联系方式。填写(“地址”,地址);
//将联系人添加到联系人列表
联系人列表。添加(联系人);
}
}捕获(最终JSONException e){
Log.e(标记“Json解析错误:”+e.getMessage());
runOnUiThread(新的Runnable(){
@凌驾
公开募捐{
Toast.makeText(getApplicationContext(),
Json分析错误:“+e.getMessage(),
吐司长度(长)
.show();
}
});
}
}否则{
e(标记“无法从服务器获取json”);
runOnUiThread(新的Runnable(){
@凌驾
公开募捐{
Toast.makeText(getApplicationContext(),
“无法从服务器获取json。请检查LogCat以了解可能的错误!”,
吐司长度(长)
.show();
}
});
}
返回null;
}
`
试试这个……希望它对您有用。非常简单,您只需像这样直接获取JSONArray对象: `
@覆盖
受保护的Void doInBackground(Void…arg0){
HttpHandler sh=新的HttpHandler();
//向url发出请求并获得响应
字符串jsonStr=sh.makeServiceCall(url);
Log.e(标签,“来自url的响应:+jsonStr”);
if(jsonStr!=null){
试一试{
//获取JSON数组节点
JSONArray联系人=新的JSONArray(jsonStr);
//通过所有触点循环
对于(int i=0;ivalue
联系人:put(“id”,id);
联系人。填写(“姓名”,姓名);
联系方式。放置(“电子邮件”,电子邮件);
联系方式。填写(“地址”,地址);
//将联系人添加到联系人列表
联系人列表。添加(联系人);
}
}捕获(最终JSONException e){
Log.e(标记“Json解析错误:”+e.getMessage());
runOnUiThread(新的Runnable(){
@凌驾
公开募捐{
Toast.makeText(getApplicationContext(),
Json分析错误:“+e.getMessage(),
吐司长度(长)
.show();
}
});
}
}否则{
e(标记“无法从服务器获取json”);
runOnUiThread(新的Runnable(){
@凌驾
公开募捐{
Toast.makeText(getApplicationContext(),
“无法从服务器获取json。请检查LogCat以了解可能的错误!”,
吐司长度(长)
.show();
}
});
}
返回null;
}
`
试试这个……希望它对你有用。好的,谢谢你,但是我怎么能把它放在我的代码中呢?事实上,我对android studio中的编码知之甚少..JsonArray listItem=new JsonArray(makeServiceCall(“);试试itOkay谢谢,但我怎么能把它放到我的代码中呢?事实上,我对android studio中的编码知之甚少..JsonArray listItem=new JsonArray(makeServiceCall(“);尝试访问此链接:访问此链接:
JsonArray listItem = new JsonArray(responseString);
@Override
protected Void doInBackground(Void... arg0) {
HttpHandler sh = new HttpHandler();
// Making a request to url and getting response
String jsonStr = sh.makeServiceCall(url);
Log.e(TAG, "Response from url: " + jsonStr);
if (jsonStr != null) {
try {
// Getting JSON Array node
JSONArray contacts = new JSONArray(jsonStr);
// looping through All Contacts
for (int i = 0; i < contacts.length(); i++) {
JSONObject c = contacts.getJSONObject(i);
String id = c.getString("nm");
String name = c.getString("cty");
String email = c.getString("hse");
String address = c.getString("yrs");
// tmp hash map for single contact
HashMap<String, String> contact = new HashMap<>();
// adding each child node to HashMap key => value
contact.put("id", id);
contact.put("name", name);
contact.put("email", email);
contact.put("address", address);
// adding contact to contact list
contactList.add(contact);
}
} catch (final JSONException e) {
Log.e(TAG, "Json parsing error: " + e.getMessage());
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Json parsing error: " + e.getMessage(),
Toast.LENGTH_LONG)
.show();
}
});
}
} else {
Log.e(TAG, "Couldn't get json from server.");
runOnUiThread(new Runnable() {
@Override
public void run() {
Toast.makeText(getApplicationContext(),
"Couldn't get json from server. Check LogCat for possible errors!",
Toast.LENGTH_LONG)
.show();
}
});
}
return null;
}