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Angular ts 3.0.1的subscribe（）上需要声明或语句_Angular_Typescript_Subscription - Fatal编程技术网
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  • Angular ts 3.0.1的subscribe（）上需要声明或语句

Angular ts 3.0.1的subscribe（）上需要声明或语句

angular typescript

Angular ts 3.0.1的subscribe（）上需要声明或语句,angular,typescript,subscription,Angular,Typescript,Subscription,我收到预期的声明或声明。我最近更新了ts和angular getTopics() { this._dataService.getTopics().subscribe(res => { this.topics = res; for (let i = 0; i < this.topics.length; i++) { if (this.topics[i]._id > this.max) {

我收到预期的声明或声明。我最近更新了ts和angular

getTopics() {
    this._dataService.getTopics().subscribe(res => {
        this.topics = res;

        for (let i = 0; i < this.topics.length; i++) {
            if (this.topics[i]._id > this.max) {
                (this.max = this.topics[i]._id);
            }
    });
}

getTopics（）{
这是._dataService.getTopics（）.subscribe（res=>{
this.topics=res；
for（设i=0；ithis.max）{
（this.max=this.topics[i]。\u id）；
}
});
}

我的错。我错过了一个}。但它在以前的版本中工作


getTopics() {
this._dataService.getTopics().subscribe(res => {
    this.topics = res;

    for (let i = 0; i < this.topics.length; i++) {
        if (this.topics[i]._id > this.max) {
            (this.max = this.topics[i]._id);
        }
    }
});
}



getTopics（）{
这是._dataService.getTopics（）.subscribe（res=>{
this.topics=res；
for（设i=0；ithis.max）{
（this.max=this.topics[i]。\u id）；
}
}
});
}