在ansible中打印子字符串的匹配数

我试图在ansible变量中打印匹配子字符串的数目。在下面的示例中，我试图打印

2

，因为

abc

在变量

vara

中出现了两次。并打印

3

，因为在检查变量

varb

时，

abc

出现三次

---
- hosts: localhost
  vars:
    vara: 'abc1\nabcdef'
    varb: 'def abc and abcd and abc'


  tasks:
   - debug: var=vara|regex_search('abc')
   - name: "Run this task when its condition in true"
     shell: echo abc in vara
     when:  (vara|regex_search('abc')) == 2

根据状态，您必须将

regex\u findall

过滤器与

length

功能结合使用

regex\u findall

返回列表中所有出现的

regex

。

length

过滤器返回列表中的元素数

---
- hosts: localhost
  vars:
    vara: 'abc1\nabcdef'
    varb: 'def abc and abcd and abc'
  tasks:
   - debug: var=vara|regex_findall('abc')|length
   - debug: var=varb|regex_findall('abc')|length
   - name: "Run this task when its condition in true"
     debug: msg='abc in vara'
     when:  (vara|regex_findall('abc')|length) == 2
   - name: "Run this task when its condition in true"
     debug: msg='abc in varb'
     when:  (varb|regex_findall('abc')|length) == 2

输出

PLAY [localhost] ***************************************************************

TASK [debug] *******************************************************************
ok: [localhost] => {
    "vara|regex_findall('abc')|length": "2"
}

TASK [debug] *******************************************************************
ok: [localhost] => {
    "varb|regex_findall('abc')|length": "3"
}

TASK [Run this task when its condition in true] ********************************
ok: [localhost] => {
    "msg": "abc in vara"
}

TASK [Run this task when its condition in true] ********************************
skipping: [localhost]

PLAY RECAP *********************************************************************
localhost                  : ok=3    changed=0    unreachable=0    failed=0

---

我收到了

“msg”：“在（{{var1 | regex_findall（'mystring'）| length}}）上发生了意外的模板类型错误”：预期的字符串或缓冲区“

@monk var1必须是字符串。您可以使用类型_debug-

{{var1 |类型_debug}}