批处理脚本以查找Apache Tomcat在哪个端口上运行

很快就能解决这个问题了

SET settings=D:\tomcat\conf\server.xml
FOR /F "eol=p tokens=1-2* delims==" %%A IN ('TYPE %settings% 2^> NUL ^| FINDSTR.exe /L /C:"\<Connector port\="') DO echo %%B

pause

查看server.xml，我们有（第一个是正确的）：

以及（必须删除发布评论）-并被评论为关闭：

以及：

在端口8009上定义AJP 1.3连接器

<Connector port="8009" protocol="AJP/1.3" redirectPort="8443" />

和。。以下是显示端口号的最终代码：

SET settings=D:\tomcat\conf\server.xml
FOR /F "eol=p tokens=1-2* delims==" %%A IN ('TYPE %settings% 2^> NUL ^| FINDSTR.exe /L /C:"\<Connector port\="') DO (
 SET PORT=%%B
 SET PORT=%PORT:" protocol=%
 SET PORT=%PORT:"=%

 goto :break
)
:break
pause

SET settings=D:\tomcat\conf\server.xml
对于/F“eol=p tokens=1-2*delims==”%%A IN（'TYPE%settings%2^>NUL^| FINDSTR.exe/L/C:\
@echo off
SET settings=D:\tomcat\conf\server.xml
对于/F“eol=p tokens=1-2*delims==”%%A IN（'TYPE%settings%2^>NUL^| FINDSTR.exe/L/C:“\n所以第一个始终是正确的？
<Connector port="8443" protocol="HTTP/1.1" SSLEnabled="true"
           maxThreads="150" scheme="https" secure="true"
            clientAuth="false" sslProtocol="TLS" />

<Connector port="8009" protocol="AJP/1.3" redirectPort="8443" />

SET settings=D:\tomcat\conf\server.xml
FOR /F "eol=p tokens=1-2* delims==" %%A IN ('TYPE %settings% 2^> NUL ^| FINDSTR.exe /L /C:"\<Connector port\="') DO (
 SET PORT=%%B
 SET PORT=%PORT:" protocol=%
 SET PORT=%PORT:"=%

 goto :break
)
:break
pause

@echo off

SET settings=D:\tomcat\conf\server.xml
FOR /F "eol=p tokens=1-2* delims==" %%A IN ('TYPE %settings% 2^> NUL ^| FINDSTR.exe /L /C:"\<Connector port\="') DO (
 echo %%B
 goto :break
)
:break
pause