Arrays JSON：指向数组项的链接

我的JSON：

[{"status":"success","id":1,"title":"title1","content":"test"},
{"status":"success","id":2,"title":"title2","content":"test2"},
{"status":"success","id":3,"title":"title3","content":"test3"},
{"status":"success","id":4,"title":"title4","content":"test4"}]

我的Ajax请求中包含以下成功函数：

function(response){

    response.forEach(function(data) {

 $('#suche').append('<li id="post_id_' + data.id + '" ><a href="#detailedpost" class="item-link item-content"><div class="item-inner"><div class="item-title">' + data.title + '</div></div></a></li>');

    })//foreach end

 }

---

如何为该ID分配正确的内容“test3”？

假设您发布的是

response

[{"status":"success","id":1,"title":"title1","content":"test"},
{"status":"success","id":2,"title":"title2","content":"test2"},
{"status":"success","id":3,"title":"title3","content":"test3"},
{"status":"success","id":4,"title":"title4","content":"test4"}];

当您单击每个元素时，下面的代码应该显示与它关联的内容

function(response){
   response.forEach(function(data) {

       $('#suche').append('<li id="post_id_' + data.id + '" ><a href="#detailedpost" class="item-link item-content"><div class="item-inner"><div class="item-title">' + data.title + '</div></div></a></li>');

       $(document).on('click', '#post_id_'  + data.id, function(){
           $('#postcontent').html(data.content);   //replace content instead of appending
       });
   })//foreach end
}

功能（响应）{
response.forEach（函数（数据）{
$（“#suche”）.append（“
”）；
$（document）.on（'click'，'#post_id_'+data.id，function（））{
$（'#postcontent'）.html（data.content）；//替换内容而不是追加
});
})//前端
}

你发布的代码有什么问题？我得到了错误的内容你得到了哪一个？

数据

的内容是什么？您是否将单击处理程序代码放入了

.forEach

块中？事实上，我觉得还可以。你遇到了什么样的问题？是的，但我得到了所有项目的结果

function(response){
   response.forEach(function(data) {

       $('#suche').append('<li id="post_id_' + data.id + '" ><a href="#detailedpost" class="item-link item-content"><div class="item-inner"><div class="item-title">' + data.title + '</div></div></a></li>');

       $(document).on('click', '#post_id_'  + data.id, function(){
           $('#postcontent').html(data.content);   //replace content instead of appending
       });
   })//foreach end
}